Question

这是我关于Stack Overflow的第一个问题。如果我在学习如何在这里工作的时候我不做正确的事情，请提前道歉。

这是我的代码：

public void TestSerialize()
{
    ShoppingBag _shoppingBag = new ShoppingBag();
    Fruits _fruits = new Fruits();
    _fruits.testAttribute = "foo";

    Fruit[] fruit = new Fruit[2];
    fruit[0] = new Fruit("pineapple");
    fruit[1]= new Fruit("kiwi");

    _fruits.AddRange(fruit);

    _shoppingBag.Items = _fruits;

    Serialize<ShoppingBag>(_shoppingBag, @"C:\temp\shopping.xml");
}

public static void Serialize<T>(T objectToSerialize, string filePath) where T : class
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));

    using (StreamWriter writer = new StreamWriter(filePath))
    {
        serializer.Serialize(writer, objectToSerialize);
    }
}

[Serializable]
public class ShoppingBag
{
    private Fruits _items;

    public Fruits Items
    {
        get { return _items; }
        set {_items = value; }
    }
}

public class Fruits : List<Fruit>
{
    public string testAttribute { get; set; }
}

[Serializable]
public class Fruit 
{
    public Fruit() { }

    public Fruit(string value)
    {
        Name = value;
    }

    [XmlAttribute("name")]
    public string Name { get; set; }
}

它产生这个XML：

<?xml version="1.0" encoding="utf-8" ?> 
<ShoppingBag xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Items>
    <Fruit name="pineapple" /> 
    <Fruit name="kiwi" /> 
  </Items>
</ShoppingBag>

我不明白为什么我没有得到<Items testAttribute="foo">

请有人告诉我需要添加到我的代码中，以便Serializer将此属性写出来吗？

谢谢，

Answer 1

你需要一个中间课：

class Program
{
    static void Main()
    {
        var shoppingBag = new ShoppingBag
        {
            Items = new ShoppingBagItems
            {
                Fruits = new List<Fruit>(new[] {
                    new Fruit { Name = "pineapple" },
                    new Fruit { Name = "kiwi" },
                }),
                TestAttribute = "foo"
            }
        };
        var serializer = new XmlSerializer(typeof(ShoppingBag));
        serializer.Serialize(Console.Out, shoppingBag);
    }
}

public class ShoppingBag
{
    public ShoppingBagItems Items { get; set; }
}

public class ShoppingBagItems
{
    [XmlElement("Fruit")]
    public List<Fruit> Fruits { get; set; }

    [XmlAttribute("testAttribute")]
    public string TestAttribute { get; set; }
}

public class Fruit
{
    [XmlAttribute("name")]
    public string Name { get; set; }
}

另请注意，您不需要使用[Serializable]属性来装饰类，因为它仅用于二进制序列化。另一个注意事项是，您不需要从List<T>派生，只需将其用作属性。

Answer 2

不幸的是，在序列化集合时，XmlSerializer没有考虑该集合的额外属性。它只考虑实施ICollection<T>的成员。如果要序列化额外属性，则需要将该集合包装在另一个不是集合本身的类中。

C＃XML Serializer不会存储属性

2 个答案: