Question

我正试图在我的ngFor中迭代我的结果 - 它不像Angular 1那么直观。我有以下内容：

search.service.ts

import {Injectable} from 'angular2/core';
import {Http, HTTP_PROVIDERS, Response} from 'angular2/http';
import 'rxjs/add/operator/map';

@Injectable()
export class SearchService {

  constructor( private _http: Http ) {

  }

  DoGeneralSearch(s){   
    return this._http.get('http://localhost:6000/search?q=' + s)
     .map((res:Response) => res.json())
  } 
}

typeahead.ts

import {Component, Input, OnChanges} from "angular2/core";
import {SearchService} from "../../../services/search.service";

@Component({
  selector: "typeahead",
  providers: [SearchService],
  template : `
    <div>{{searchSvc | async | json}}</div>
    <div id="typeaheadRooms" *ngIf="searchSvc">
      <div class="typeaheadRowRooms" *ngFor="#item of searchSvc?.rooms">
        <div class="typeaheadRoomTitle">{{item.name}}}</div>
      </div>
      <div class="typeaheadRowRooms" *ngFor="#item of searchSvc?.colors">
        <div class="typeaheadRoomTitle">{{item.name}}}</div>
      </div>
`,
})
export class TypeaheadComponent implements OnChanges {

  @Input() txt: string;
  display = false;

  ngOnChanges(changes: {[propName: string]: SimpleChange}) {
    var search = changes['txt'].currentValue;
    if(search.length > 2) {
        this.display = true;
        this.searchSvc = this._searchService.DoGeneralSearch(search);
    }
    else
    {
        this.display = false;
    }
  }

  constructor(private _searchService: SearchService) {}
}

json中的典型结果：

{  
"max":20,
"queryString":"chem",
"rooms":[  
  {  
     "name":"Lima"
  },
  {  
     "name":"Delta"
  }
 ],
"colors":[  
  {  
     "name":"Red"
  },
  {  
     "name":"Lime"
  }
 ]

}

发生了什么事？好吧，{{searchSvc | async | json}}告诉我结果。但是ngFor：否:(

任何线索？谢谢你提前!!!

Answer 1

在这种情况下，您需要使用：

<div class="typeaheadRowRooms" *ngFor="#item of searchSvc | async">

并按照以下方式更新您的服务：

DoGeneralSearch(s){   
  return this._http.get('http://localhost:6000/search?q=' + s)
     .map((res:Response) => res.json().rooms);
}

修改

如果你想从observable接收完整的对象，我会看到两种方法：

明确订阅：

this._searchService.DoGeneralSearch(search).subscribe( (data) => { this.searchSvc = data; } );

并在模板中

<div class="typeaheadRowRooms" *ngFor="#item of searchSvc?.rooms">

自定义管道以获取rooms数据：

@Pipe({name: 'field'}) export class FieldPipe implements PipeTransform { transform(value, args:string[]) : any { return value[args[0]]; } }

并在模板中

<div class="typeaheadRowRooms" *ngFor="#item of searchSvc | async | field:rooms">

Angular 2 - 在http请求（服务）后显示结果

1 个答案: