Question

更新尝试使用FileTransfer插件使用以下代码将文件发布到transloadit

     var uri = encodeURI("https://api2-eu-west-1.transloadit.com/assemblies");
            var options = new FileUploadOptions();
            options.fileKey = "file";
            options.fileName = filepath.substr(filepath.lastIndexOf('/') + 1);

            var params = new Object();
            params.auth =new Object();
            params.auth.key ="***************" ;

            options.params = params; 
            var ft = new FileTransfer();
            ft.upload(filepath, uri, win, fail, options);

我收到错误＆＃34; no_params_field＆＃34;，＆＃34;没有参数字段提供＆＃34; 我也试过传递params作为选项

    ft.upload(filepath, uri, win, fail, params);

请帮助您如何使用FileTransfer插件发送transloadit params？

由于

Answer 1

找到它，它应该作为

传递

    var params = {};
            params.params = new Object();
            params.params.auth = {key: "***"};

然后

    ft.upload(filepath, uri, win, fail, {params: params});

由于

Cordova FIle Transfer插件如何传递transloadit参数？

1 个答案: