Question

这是演示课程的主要方法。

我的班级应该有以下变量：双倍宽度，高度，它应该有这些方法：SetWidthHeight（double W，double H），GetVolume（）。

     import java.util.*;


        public class egypt
        {
           public static void main(String[] args)
           {
              Scanner in = new Scanner(System.in);
              Pyramid Luxor = new Pyramid();
              double W, H;
              System.out.println("Enter Luxor's width:");
              W = in.nextDouble();
              System.out.println("Enter Luxor's height:");
              H = in.nextDouble();

              Luxor.SetWidthHeight(W, H);
              System.out.println("Luxor has volume of " + Luxor.GetVolume());
              System.out.println("Luxor has a Surface Area of " + getSurfaceArea());
           }
        }

       //This class describes pyramids with a square base.

        class Pyramid
        {
          private double Height;
          private double Width ;

          public Pyramid(double W, double H)
           {
                Height = H; Width = W;
        }

           public double GetVolume()
           {
              return Height * Width * Width / 3;
           }


           public double getSurfaceArea()
           {
              double sideLength = Math.sqrt(Height * Height
                 + Width * Width/ 4);
              return 2 * Width * sideLength;
           }
        }

错误

C：\ Users \ A1.D257 \ Desktop \ jaava \ egypt.java：8：错误：构造函数   类Pyramid中的金字塔不能应用于给定类型;         金字塔卢克索=新金字塔（）;                         ^ required：double，double found：无参数原因：实际和形式参数列表的长度不同

C：\ Users \ A1.D257 \ Desktop \ jaava \ egypt.java：15：错误：找不到   符号         Luxor.SetWidthHeight（W，H）;              ^符号：方法SetWidthHeight（double，double）location：变量类型为Pyramid的Luxor

C：\ Users \ A1.D257 \ Desktop \ jaava \ egypt.java:17：错误：找不到   符号         System.out.println（“Luxor的表面积为”+ getSurfaceArea（））;                                                             ^符号：方法getSurfaceArea（）location：class egypt 3 errors

工具已完成，退出代码为1

Answer 1

您的编译器错误：

1）egypt.java的第8行 - 无法创建Pyramid（）因为你只有一个构造函数并且它需要两个参数

 public Pyramid(double W, double H)
 {
        Height = H; Width = W;
 }

2）egypt.java的第15行 - 你从未在类Pyramid.java中创建函数SetWidthHeight（）

3）egypt.java第17行getSurfaceArea（）未在此范围内定义 - 只需要调用 Luxor 时出现一点错误.getSurfaceArea（）

修正了错误，以准确向您展示如何改进代码

import java.util.*;

// Class name should start uppercase
public class Egypt
{
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        Pyramid luxor; // start with lowercase
        double width, height; // start with lowercase

        // Get input values
        System.out.println("Enter Luxor's width:");
        width = in.nextDouble();
        System.out.println("Enter Luxor's height:");
        height = in.nextDouble();

        // Initialize variable
        luxor = new Pyramid(width, height);

        System.out.println("Luxor has volume of " + luxor.getVolume());
        System.out.println("Luxor has a Surface Area of " + luxor.getSurfaceArea());
    }
}

// This class describes pyramids with a square base.
public class Pyramid
{
    private double height;
    private double width;

    public Pyramid(double width, double height)
    {
        this.height = height; this.width = width;
    }

    public double getVolume()
    {
        return height * width * width / 3;
    }


    public double getSurfaceArea()
    {
        double sideLength = Math.sqrt(height * height
                + width * width/ 4);
        return 2 * width * sideLength;
    }
}

我正在尝试为金字塔编写类定义。但由于某种原因，它想要运行。我是初学者，非常迷失

1 个答案: