如何检查所有zip文件?
var reader: ZipFileReader = new ZipFileReader();
reader.addEventListener(ZipEvent.ZIP_DATA_UNCOMPRESS, zipDataUncompressHandler);
var zipFile: File = new File(zipFilePath);
reader.open(zipFile);
var list: Array = reader.getEntries();
zipFileCount = list.length;
trace(zipFileCount + " Numbers of items");
for each(var entry: ZipEntry in list) {
var filename: String = entry.getFilename();
if (entry.isDirectory()) {
trace("DIR --->" + filename);
} else {
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount = zipFileWritedCount + 1;
}
function zipDataUncompressHandler(e: ZipEvent): void {
var entry: ZipEntry = e.entry;
var zfile: File = File.userDirectory.resolvePath('somefolder' + File.separator + entry.getFilename());
var fs: FileStream = new FileStream();
fs.open(zfile, FileMode.WRITE);
fs.writeBytes(e.data);
fs.close();
trace("Refresh Scene");
//include "RefreshScene.as";
}
我的文件被解压缩,但我需要检查实际提取的所有文件。 我有什么方法可以做到这一点。
我在使用zip文件时正在使用 airxzip 。
此外,如果我可以添加装载程序。
答案 0 :(得分:0)
您可以缩短zipFileWritedCount = zipFileWritedCount + 1;
仅使用zipFileWritedCount +=1;
或偶数
zipFileWritedCount++;
Equality ==
manual 。快速举例:
for each(var entry: ZipEntry in list)
{
var filename: String = entry.getFilename();
if ( entry.isDirectory() ) { trace("DIR --->" + filename); }
else
{
trace("FILE --->" + filename + "(" + entry.getCompressRate() + ")");
reader.unzipAsync(entry);
}
zipFileWritedCount += 1; //add plus 1
if ( zipFileWritedCount == zipFileCount ) //if Equal to zipFileCount..
{
trace ("unzipped all files...");
trace ("zipFileCount: " + zipFileCount + " -VS- " + "zipFileWritedCount: " + zipFileWritedCount )
}
}