Question

我有一个班级，用户输入有关员工的信息（姓名，地址，雇用日期），以确定用户确定的员工人数。

import java.util.ArrayList;
import java.util.Scanner;

public class Employee {
    public static void main(String [] args){
        String employeeName = null;
        String employeeAddress = null;
        String hireDate = null;

        Scanner userInput = new Scanner(System.in);
        System.out.println("How many employees would you like to enter information for?");
        int numEmployees = userInput.nextInt();

        for( int i = 0; i < numEmployees; i++) {
            Scanner input = new Scanner(System.in);
            System.out.println("Enter employees first name: ");
            String firstName = input.nextLine();
            System.out.println("Enter employees last name: ");
            String lastName = input.nextLine();
            System.out.println("Enter street employee lives on:");
            String street = input.nextLine();
            System.out.println("Enter city employee lives in:");
            String city = input.nextLine();
            System.out.println("Enter state employee lives in:");
            String state = input.nextLine();
            System.out.println("Enter employee's zip code:");
            String zip = input.nextLine();
            System.out.println("Enter month employee was hired:");
            String month = input.nextLine();
            System.out.println("Enter day employee was hired:");
            String day = input.nextLine();
            System.out.println("Enter year employee was hired:");
            String year = input.nextLine();

            Name name = new Name(firstName, lastName);
            Address address = new Address(street, city, state, zip);
            Date date = new Date(month, day, year);

            employeeName = name.getName();
            employeeAddress = address.getAddress();
            hireDate = date.getDate();

            ArrayList<String> obj = new ArrayList<String>();
            obj.add(employeeName);
            obj.add(employeeAddress);
            obj.add(hireDate);
            System.out.println(obj);
        }
    }
}

我正在尝试让程序通过用户提示，获取该信息并将其放在ArrayList中的某个位置，然后重复多次用户先前确定并在结束时一次显示所有内容。像这样：

FirstName LastName, Address, Hire Date
FirstName LastName, Address, Hire Date

等等。现在，我的代码将通过用户提示运行，显示该代码，然后运行下一轮提示并显示：

Enter Name:
 Name
Enter Address:
 Address
Enter Hire Date:
 Hire Date

[Name, Address, Hire Date]

Enter Name:
 Name
Enter Address:
 Address
Enter Hire Date:
 Hire Date

[Name, Address, Hire Date]

我意识到这是因为我的数组和数组显示在for循环中，但当我将数组移到循环外时，我得不到显示。当我只在循环外移动数组显示时，我的代码无法编译。

Answer 1

移动此行：

System.out.println(obj);

超出for循环。并使用List来包含ArrayList。然后将其显示在单独的for循环中：

List<ArrayList<String>> objs = new ArrayList<ArrayList<String>>(); //use list of objs
for( int i = 0; i < numEmployees; i++ )
{
    //all the inputs

    ArrayList<String> obj = new ArrayList<String>();
    obj.add(employeeName);
    obj.add(employeeAddress);
    obj.add(hireDate);
    objs.add(obj);

}

for( int i = 0; i < numEmployees; i++ ) //for loop just to display
    System.out.println(objs.get(i)); //display each element here

Answer 2

您要打印的是[string，string，string]类型的元组。这可以表示为List。然后，对于每个员工，您要将此元组存储在另一个类型为List<List<String>>的列表中。

public static void main( String [] args )
{

    String employeeName = null;
    String employeeAddress = null;
    String hireDate = null;

    Scanner userInput = new Scanner(System.in);
    System.out.println("How many employees would you like to enter information for?");
    int numEmployees = userInput.nextInt();
    List<List<String>> employesInfo = new ArrayList<List<String>>();

    for( int i = 0; i < numEmployees; i++ )
    {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter employees first name: ");
        String firstName = input.nextLine();
        System.out.println("Enter employees last name: ");
        String lastName = input.nextLine();
        System.out.println("Enter street employee lives on:");
        String street = input.nextLine();
        System.out.println("Enter city employee lives in:");
        String city = input.nextLine();
        System.out.println("Enter state employee lives in:");
        String state = input.nextLine();
        System.out.println("Enter employee's zip code:");
        String zip = input.nextLine();
        System.out.println("Enter month employee was hired:");
        String month = input.nextLine();
        System.out.println("Enter day employee was hired:");
        String day = input.nextLine();
        System.out.println("Enter year employee was hired:");
        String year = input.nextLine();

        Name name = new Name(firstName, lastName);
        Address address = new Address(street, city, state, zip);
        Date date = new Date(month, day, year);

        employeeName = name.getName();
        employeeAddress = address.getAddress();
        hireDate = date.getDate();

        ArrayList<String> obj = new ArrayList<String>();
        obj.add(employeeName);
        obj.add(employeeAddress);
        obj.add(hireDate);

        employeesInfo.add(obj);
    }

    for (int i = 0; i < numEmployees; i++ ) {
        System.out.println(emploeesInfo.get(i));
    }
}

如何让我的java ArrayList正确显示？

2 个答案: