Question

我有一个gls模型，我在其中将一个公式（来自另一个对象）分配给模型：

equation <- as.formula(aic.obj[row,'model'])
> equation
temp.avg ~ I(year - 1950)
mod1 <- gls(equation, data = dat)

> mod1
Generalized least squares fit by maximum likelihood
  Model: equation 
  Data: dat 
  Log-likelihood: -2109.276

然而我不希望“模型”成为“方程式”而是“quation”本身！我该怎么办？

Answer 1

这是非常标准的，即使lm会这样做。一种方法：劫持print.gls函数

library('nlme')

(form <- follicles ~ sin(2*pi*Time) + cos(2*pi*Time))
# follicles ~ sin(2 * pi * Time) + cos(2 * pi * Time)

(fm1 <- gls(form, Ovary))

# Generalized least squares fit by REML
#   Model: form
#   Data: Ovary 
#   Log-restricted-likelihood: -898.434
# 
# Coefficients:
#   (Intercept) sin(2 * pi * Time) cos(2 * pi * Time) 
#    12.2155822         -3.3396116         -0.8697358 
# 
# Degrees of freedom: 308 total; 305 residual
# Residual standard error: 4.486121 

print.gls <- function(x, ...) {
  x$call$model <- get(as.character(x$call$model))
  nlme:::print.gls(x, ...)
}

fm1

# Generalized least squares fit by REML
#   Model: follicles ~ sin(2 * pi * Time) + cos(2 * pi * Time) 
#   Data: Ovary 
#   Log-restricted-likelihood: -898.434
# 
# Coefficients:
#   (Intercept) sin(2 * pi * Time) cos(2 * pi * Time) 
#    12.2155822         -3.3396116         -0.8697358 
# 
# Degrees of freedom: 308 total; 305 residual
# Residual standard error: 4.486121

Answer 2

你可以通过一些巧妙的语言修改来解决这个问题。这会创建（未评估的）gls调用，并直接插入模型方程，然后对其进行评估。

cl <- substitute(gls(.equation, data=dat), list(.equation=equation))
mod1 <- eval(cl)

R：使用as.formula修复模型中的模型调用

2 个答案: