我在c中编写了一个函数,它将一个字节(unsigned char)BCD字符串转换为ASCII。请查看代码并提出一些改进建议。
还有其他有效的方法可以将BYTE BCD转换为ASCII。
BYTE_BCD_to_ASC(BYTE *SrcString, char *DesString)
{
switch (((BCD *)SrcString)->l)
{
case 10:/*A*/
case 11:/*B*/
case 12:/*C*/
case 13:/*D*/
case 14:/*E*/
case 15:/*F*/
*DesString = (char)(((BCD *)SrcString)->l + '0' + 7);
break;
default:
*DesString = (char)(((BCD *)SrcString)->l + '0');
break;
}
switch (((BCD *)SrcString)->h)
{
case 10:
case 11:
case 12:
case 13:
case 14:
case 15:
*(DesString + 1) = (char)(((BCD *)SrcString)->h + '0' + 7);
break;
default:
*(DesString + 1) = (char)(((BCD *)SrcString)->h + '0');
break;
}
*(DesString + 2) = '\0';
}
谢谢
Fakhar
答案 0 :(得分:5)
我想我会做这样的事情:
void BCD2ASC(unsigned char src, char *dest) {
static const char outputs[] = "0123456789ABCDEF";
*dest++ = outputs[src>>4];
*dest++ = outputs[src&0xf];
*dest = '\0';
}
答案 1 :(得分:2)
试试这个:
void BCD_To_ASCII(unsigned char bcd_value, char * p_ascii_text)
{
//--------------------------------------------------
// BCD contains digits 0 .. 9 in the binary nibbles
//--------------------------------------------------
*p_ascii_text++ = (bcd_value >> 4) + '0';
*p_ascii_text++ = (bcd_value & 0x0f) + '0';
*p_ascii_text = '\0';
return;
}
答案 2 :(得分:1)
最后我实现了如下例程
static const char s_szHexAscNo[] = "0123456789ABCDEF";
void BYTE_BCD_to_ASC(BYTE *SrcString, char DesString[3], int BCDflag)
{
assert(SrcString != NULL);
assert(DesString != NULL);
if ( BCDFlag_Normal == BCDflag)
{
*DesString++ = (char) s_szHexAscNo[((BCD *)SrcString)->l];
*DesString++ = (char) s_szHexAscNo[((BCD *)SrcString)->h];
}
if (BCDFlag_Reverse == BCDflag)
{
*DesString++ = (char) s_szHexAscNo[((BCD_REVERSE *)SrcString)->l];
*DesString++ = (char) s_szHexAscNo[((BCD_REVERSE *)SrcString)->h];
}
*DesString = '\0';
}
/* BCD and BCD_REVERSE are defined as */
typedef struct
{
unsigned char l : 4;
unsigned char h : 4;
} BCD;
typedef struct
{
unsigned char h : 4;
unsigned char l : 4;
} BCD_REVERSE;
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