Question

我正在寻找in place命令来更改以:.:.

结尾的所有文件行

这

chr01   1453173 .   C   T   655.85  PASS    .   GT:AD:DP:PGT:PID    0/1:25,29:54:.:.

要

chr01   1453173 .   C   T   655.85  PASS    .   GT:AD:DP    0/1:25,29:54

简而言之，我基本上会以:PGT:PID

结尾的任何行删除:.:.和:.:.

Answer 1

您正在寻找类似的内容：

sed -i.bak "/^.*:\.:\.$/ {s/:PGT:PID//g; s/:\.:\.//g;}" file

它替换为文件，并以file.bak
/^.*:\.:\.$/将s命令限制为:.:. .需要引用的行，因为它们是正则表达式的特殊字符
s sommand用空字符串

Answer 2

用awk表示：

awk 'sub(/:\.:\.$/,""){sub(/:PGT:PID/,"")} 1' file
chr01   1453173 .   C   T   655.85  PASS    .   GT:AD:DP    0/1:25,29:54

使用gawk进行内部编辑，您可以添加-i inplace选项，而只需添加> tmp && mv tmp file即可添加<section id="pre-acquisition" class="section scrollspy" markdown="1"> content </section> <section id="accessioning" class="section scrollspy" markdown="1"> content <section id="accessioning-guidelines" class="section scrollspy" markdown="1"> more content </section> <section id="accessioning-templates" class="section scrollspy" markdown="1"> even more content </section> </section>。

Answer 3

使用GNU sed和Solaris sed：

sed '/:\.:\.$/{s///;s/PGT:PID//;}' file

如果您想使用GNU sed“就地”编辑文件，请使用选项-i。

Answer 4

As a one-liner:

sed -i -e '/:\.:\.$/!n' -e 's///' -e 's/:PGT:PID//g' "$file"

Expanded:

/:\.:\.$/!n     # leave lines untouched unless they end in ":.:."
s///            # replace the matched ":.:." with nothing
s/:PGT:PID//g   # replace ":PGT:PID" with nothing, everywhere

We use the -i flag to perform in-place edits. We pass each line as a separate -e expression for portability: some sed implementations allow several commands to be concatenated with ;, but that is not required by the POSIX standard.

在一行中组合两个sed命令

4 个答案: