我是python和编程的新手
我在文件夹中有1200个文本文件,格式如下:
詹姆斯 - 1 - 如何...... .txt
莎拉 - 2 - 如何... .txt
Steph - 3 - 如何... .txt
...
玛利亚 - 200 - 如何... .txt
...
拉什福德 - 1200 - 如何... .txt
我想重命名1000以下的文件以添加前导0,以便它们都具有相同的位数,例如,0001,0050,0300
到目前为止,这是我的代码,但我被困住了:
#!python3
import os
from tkinter import filedialog
cleaned_files = []
root_folder = filedialog.askdirectory()
os.chdir(root_folder)
folder_files = os.listdir(root_folder)
# Filter out files starting with '.' and '_'
cleaned_files = []
for item in folder_files:
if item[0] == '.' or item[0] == '_':
pass
else:
cleaned_files.append(item)
# Find file names of the root folder and save them
def getFiles(files):
for file in files:
file_start, file_number, file_end = file.split('-')
file_number.strip()
# Was trying to append just one 0 to numbers <10
if int(file_number) < 10:
print(file_number)
else:
pass
getFiles(cleaned_files)
答案 0 :(得分:2)
像这样修改你的追加方法(@gtlambert和@zondo提到):
# Was trying to append just one 0 to numbers <10
file_number.zfill(4)
答案 1 :(得分:1)
正如你在评论中所说,str.zfill
是一种可能而简单的解决方案。
您只需要更改getfiles
功能:
def getFiles(files):
for file in files:
file_start, file_number, file_end = file.split('-')
num = file_number.split().zfill(4) # num is 4 characters long with leading 0
new_file = "{}- {} -{}".format(file_start, num, file_end)
# rename or store the new file name for later rename