不会从数据库中检索Listitem。它是从另一个类传递的。
答案 0 :(得分:3)
您没有“从列表视图中删除列表项目”。您可以修改支持ListAdapter
的{{1}}所拥有的数据。如果适配器是ListView
,请在ArrayAdapter
上致电remove()
。如果适配器是ArrayAdapter
,请从数据库中删除该项目,然后CursorAdapter
requery()
。等等。
答案 1 :(得分:0)
如果您使用带有ArrayList的SimpleAdapter,那就更好了。然后通过删除要删除的内容来更新列表。只需调用adapter.notifyDataSetChanged()。赞:
static final ArrayList<HashMap<String,String>> list =new ArrayList<HashMap<String,String>>();
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.newentrypagelayout);
//create base adapter for listview
adapter= new SimpleAdapter(
this,
list,
R.layout.custom_list_row,
new String[] {"pen","price","color"},
new int[] {R.id.text1,R.id.text2, R.id.text3}
);
populateList();
setListAdapter(adapter);
}
public void populateList()
{
sHashMap<String,String> temp = new HashMap<String,String>();
temp.put("pen","MONT Blanc");
temp.put("price", "200.00$");
temp.put("color", "Silver, Grey, Black");
list.add(temp);
HashMap<String,String> temp1 = new HashMap<String,String>();
temp1.put("pen","Gucci");
temp1.put("price", "300.00$");
temp1.put("color", "Gold, Red");
list.add(temp1);
HashMap<String,String> temp2 = new HashMap<String,String>();
temp2.put("pen","Parker");
temp2.put("price", "400.00$");
temp2.put("color", "Gold, Blue");
list.add(temp2);
HashMap<String,String> temp3 = new HashMap<String,String>();
temp3.put("pen","Sailor");
temp3.put("price", "500.00$");
temp3.put("color", "Silver");
list.add(temp3);
HashMap<String,String> temp4 = new HashMap<String,String>();
temp4.put("pen","Porsche Design");
temp4.put("price", "600.00$");
temp4.put("color", "Silver, Grey, Red");
list.add(temp4);
}
now if you need to delete an item.Get the selected index(the item that has been selected) remove it from the array list & call the method I told before.Like:
public void itemDeleteButtonClicked(View v)
{
int index=itemsListView.getSelectedItemPosition();
list.remove(index);
adapter.notifyDataSetChanged();
}