我想更新Entity Framework中的多个列。我现在用这个:
var user = new Relations { Id=1, Status = 1, Date = DateTime.Now, Notification = 0 };
db.Relations.Attach(user);
db.Entry(user).Property(x => x.Status).IsModified = true;
db.Entry(user).Property(x => x.Notification).IsModified = true;
db.Entry(user).Property(x => x.Date).IsModified = true;
db.Configuration.ValidateOnSaveEnabled = false;
db.SaveChanges();
有没有更好的方法来更新列而不重复代码db.Entry(user).Property
几次?
答案 0 :(得分:3)
你可以使用EntityState
像这样:
var user=db.users.Find(userId);
user.name="new name";
user.age=txtAge.text;
user.address=txtAddress.text;
context.Entry(user).EntityState=Entitystate.Modified;
答案 1 :(得分:1)
我更喜欢使用:
var existingUser = context.Set<User>().Where(u => u.Id == 1);
context.Entry(existingUser).CurrentValues.SetValues(user);
或者你可以使用像GraphDiff这样的第三个库。
答案 2 :(得分:1)
哟更新您不需要执行此操作的实体:
// build your entity object with new values
var user = new Relations { Id=1, Status = 1, Date = DateTime.Now, Notification = 0 };
//attach as modified in one single step
db.Entry(user).State = EntityState.Modified;
//execute update
db.SaveChanges();
这假设您正在设置所有实体字段,并且您的实体中没有RowVersion字段。管理这些其他情况需要额外的步骤。
答案 3 :(得分:0)
试试这个,
var app = angular.module("productsApp", [])
.service("serviceProvider", function ($http) {
this.getDatas = function getDatas(data) {
return $http({
method: 'POST', url: serviceUrl + '/GetProductsByCategoryOrName', headers: {
'Authorization': apiKey
},
data: data
})
}
return this
});
function GetController($scope, serviceProvider) {
var data = { "query": "grocery", "categoryId": "976759", "pageIndex": 0, "sortDirection": "asc" };
serviceProvider.getDatas(data).then(function (response) {
$scope.products = response.data.data;
});
}
function searchProductsController($scope, serviceProvider) {
var data = { "query": $scope.searchText, "categoryId": "976759", "pageIndex": 0, "sortDirection": "asc" };
$scope.submit = function () {
serviceProvider.getDatas(data).then(function (response) {
console.log(response.data.data);
$scope.products = response.data.data;
});
}
};
答案 4 :(得分:0)
当通过上下文获取项目时
除非您更改默认行为,否则会在该上下文中自动跟踪。
所以你可以这么简单:
var txtInputAge = 18;
var txtAdrressLine1 = "Some cool place"
//fetch the user
var user = db.Users.Find(userId);
//change the properties
user.Name = "new cooler name";
user.Age = txtInputAge;
user.Address = txtAdrressLine1;
//call save changes
db.SaveChanges();
更新 - 添加看起来像
//create new entry
User user = new User();
user.Name = "new cooler name";
user.Age = txtInputAge;
user.Address = txtAdrressLine1;
//add to context
db.Users.Add(user);
//call save changes
db.SaveChanges();