Question

我有这个代码用PHP和HTML在每个表行上生成按钮：

<!DOCTYPE HTML>
  <h2 class="text-center">Consulta</h2>
  <br>
  <table class="table table-striped">
    <tr class="info">
      <td class="black"><span style="font-weight:bold">#</span></td>
      <td class="black"><span style="font-weight:bold">Data</span></td>
      <td class="black"><span style="font-weight:bold">Condomínio</span></td>
      <td class="black"><span style="font-weight:bold">Entrada</span></td>
      <td class="black"><span style="font-weight:bold">Título</span></td>
      <td class="black"><span style="font-weight:bold">Autor</span></td>
      <td class="black"><span style="font-weight:bold">Estado</span></td>
      <td class="black"><span style="font-weight:bold"></span></td>
    </tr>
    <?php
    $select = "SELECT * FROM database";
    $get = mysqli_query($cnn, $select) or die ('error');
    while($row = mysqli_fetch_array($get, MYSQLI_ASSOC)) {
      echo "<tr>";
      echo "<td>";
      echo $row['id'];
      echo "</td><td>";
      echo $row['data'];
      echo "</td><td>";
      echo $row['condominio'];
      echo "</td><td>";
      echo $row['entrada'];
      echo "</td><td>";
      echo $row['titulo'];
      echo "</td><td>";
      echo $row['autor'];
      echo "</td><td>";            
      echo $row['estado'];
      echo "</td><td>";    
      $html = '<form role="form" class="form-inline" method="POST" enctype="multipart/form-data" action="thispage.php">';
      echo $html;
      echo '<button type="submit" name="alter'.$row['id'].'" id="alter'.$row['id'].'" class="btn btn-default btn-xl">alter'.$row['id'].'</a></button>';
      echo '</form>';

      echo "</td>";
      echo "</tr>";
    }
    echo "</table>";
?>
</html>

当然，我想使用按钮，但下面的代码对我不起作用：

<?php
$var = "row['id']";
$var2 = "alter".$var;
if (isset($_POST['$var2'])) {
  echo('some code');
} 
?>

我看到了一些使用Javascript的解决方案，但我只能使用PHP和HTML，所以如果有人可以提供帮助，我会很感激。

Answer 1

以简单的方式将按钮替换为链接

当你获得数据时，就像这样的链接

echo " <a href='?id=".$row['id']."'>'alter'".$row['id']."</a>"

在下一页中使用它

if(isset($_GET['id']))
{
do something 
}

Answer 2

if (isset($_POST[$var2])) {
  echo('some code');
}

试试这个。我想$var2被视为一个字符串，因为它被单引号

覆盖

Answer 3

如果$ var2应该读为“alter1”，“alter2”，“alter3”等等，那么

$var = "row['id']";

应该阅读，

$var = $row['id'];

克雷格

使用PHP和HTML在每个表行上生成按钮

3 个答案: