没有类似字符的密码迭代？

Question

我正在阅读这篇thread，这激发了我一些研究如何优化简单生成密码的暴力破解。

我的遭遇：

我试图从key=''.join(random.sample(string.uppercase, 7))迭代所有可用的密码组合。如果我已经阅读了正确的文档：key在这种情况下，不能包含两个相似或相等的字母。它总是（在这种情况下）唯一的7长大写字符串。

• 示例：str(key) 无法生成：AARGHJU

问题：

如何更改while语句，使其不会迭代包含相似字母的字符串？

chars = 'ABCDEFGHIJKLMNOPQRSTUVXYZ' # chars to look for
try:
    while 1:
        # Iteration processess of possibel keys
        for length in range(7,8): # only do length of 7
            to_attempt = product(chars, repeat=length)
            for attempt in to_attempt:
                print(''.join(attempt))

except KeyboardInterrupt:
    print "Keybord interrupt, exiting gracefully anyway."
    sys.exit()

生成ex会产生不必要的时间和力量：

AAAFXEL
AAAFXEM
AAAFXEN
AAAFXEO
AAAFXEP
AAAFXEQ
AAAFXER
AAAFXES

Answer 1

对于整个空间的非重复枚举，也许你想要itertools.permutations。

```python
from itertools import permutations
chars = 'ABCDEFGHIJKLMNOPQRSTUVXYZ' # chars to look for
try:
    while 1:
        # Iterate through possible keys
        for length in range(7,8):
            to_attempt = permutations(chars, length)
            for attempt in to_attempt:
                print(''.join(attempt))

except KeyboardInterrupt:
    print "Keyboard interrupt, exiting gracefully anyway."
    sys.exit()
```