Question

我有一系列哈希，

[
 {id: 1, tool_id: 1, user_ids: [1]},
 {id: 2, tool_id: 2, user_id: [2]},
]

我想搜索它，如果有某个tool_id，我想将user_id附加到user_ids列表。

Answer 1

说user_id 100 tool_id = 1为arr.each { |a| a[:user_ids] << 100 if a[:tool_id] == 1 } #=> [{:id=>1, :tool_id=>1, :user_ids=>[1, 100]}, {:id=>2, :tool_id=>2, :user_id=>[2]}]：

  public function actionUpdate($id)
{
    $model = $this->findModel($id);

    if ($model->load(Yii::$app->request->post())) {
        $model->start_date = strtotime($model->start_date);
        $model->start_date = date('Y-m-d',$model->start_date);
        $model->end_date = strtotime($model->end_date);
        $model->end_date = date('Y-m-d',$model->end_date);
        $model->date_of_request = strtotime($model->date_of_request);
        $model->date_of_request = date('Y-m-d',$model->date_of_request);
        //$model->start_date = date_format($model->start_date,'Y-m-d');
       if($model->save()){
         return $this->redirect(['view', 'id' => $model->id]);
       }else{
          return $this->render('create', [
            'model' => $model,
         ]);



       }
   } else {
       return $this->render('create', [
            'model' => $model,
      ]);


  //new line

Answer 2

鉴于

h = [
 {id: 1, tool_id: 1, user_ids: [1]},
 {id: 2, tool_id: 2, user_id: [2]},
]

尝试

def add_user_id(h, tid, uid)
 el = h.find { |i| i[:tool_id] == tid }
 el[:user_id] << uid if el
end 

add_user_id(h, 2, 3)
p h

输出

[{：id =＆gt; 1，：tool_id =＆gt; 1，：user_ids =＆gt; [1]}，{：id =＆gt; 2，：tool_id =＆gt; 2，：user_id =＆gt; [ 2,3]}]

Answer 3

使用Enumerable#find()的简短版本。（没有处理未知tool_id值。）

# add the user_id 4 to the hash with the tool_id 2
arr.find { |e| e[:tool_id] == 2 }[:user_ids] << 4

在Ruby中搜索哈希数组后更新哈希

3 个答案: