Question

我试图弄清楚如何使用下面的函数获取当前时间戳，但我想格式化它，以便在输出时显示4:30:23的时间。最后我想在运行算法之前和之后减去时间戳。

struct timeval FindTime() {     
    struct timeval tv;    
    gettimeofday(&tv,NULL);
    return tv;
}

int main() { 
    printf("%ld\n",FindTime());
    return0;
}

当前输出格式： 1456178100

Answer 1

阅读strftime。

我想你想要%T？

Answer 2

这可能是你需要的吗？

#include <time.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>

struct setClock{
    int hour;
    int minutes;
    int seconds;
};

struct setClock currTime(void);
void timeCheck(struct setClock myClock[2]);

int main(void){
    struct setClock myClock[2];

    myClock[0] = currTime();
    printf("Start Time: %d:%d:%d\n\n", myClock[0].hour, myClock[0].minutes, myClock[0].seconds );

    sleep(5);
    /*  CODE HERE  */

    myClock[1] = currTime();
    printf("End Time:   %d:%d:%d\n", myClock[1].hour, myClock[1].minutes, myClock[1].seconds );

    timeCheck(myClock);

    return 0;

}

struct setClock currTime(void){
    struct setClock ret;
    struct tm *tm;
    time_t myTime;

    myTime=time(NULL);
    tm=localtime(&myTime);

    ret.hour = tm->tm_hour;
    ret.minutes = tm->tm_min;
    ret.seconds = tm->tm_sec;

    return ret;
}

void timeCheck(struct setClock myClock[2]){
    int hour;
    int minute;
    int second;

    time_t end, start;
    double diff;

    start = (time_t)((myClock[0].hour * 60 + myClock[0].minutes) * 60 + myClock[0].seconds) ;
    end   = (time_t)((myClock[1].hour * 60 + myClock[1].minutes) * 60 + myClock[1].seconds) ;

    if( end < start ){
        end += 24 * 60 * 60 ;
    }

    diff = difftime(end, start);

    hour = (int) diff / 3600;
    minute = (int) diff % 3600 / 60;
    second = (int) diff % 60;

    printf("\n\n");
    printf("The elapsed time is  %d Hours - %d Minutes - %d Seconds.\n", hour, minute, second);
}

输出：

Start Time: 23:19:18

End Time:   23:19:23


The elapsed time is  0 Hours - 0 Minutes - 5 Seconds

Answer 3

您可以使用此代码使用String函数来捕获时间

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <String.h>


int main()
{
 time_t timeLine;
struct tm * timeInfo;

time ( &timeLine );
timeInfo = localtime ( &timeLine );
printf ( "%s", asctime (timeInfo) );

return 0;
}

如何格式化C中的时间戳

3 个答案: