我试图完成我的项目并遇到计算payment
的问题。在addCustomer()
函数中,我调用了calcMonthlyPayment()
函数。在calcMonthlyPayment()
函数中,当我打印payment
变量时,它会显示正确的答案。但在返回并在payment
函数中打印addCustomer()
变量后,它将打印为0.00。我不确定我是否遗漏了一些简单的东西?谢谢你的建议!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include "person.h"
// Program Contstants
#define INTEREST .03
#define CHAR_LEN 40
#define MAX_CUST 100
#define MIN_PRIN 1000
#define MAX_PRIN 1000000
#define MIN_TERM 5
#define MAX_TERM 30
// Program Variables
struct person *customer = NULL;
float payment;
// Function Prototypes
void addCustomer();
struct person *findCustomer(int custID);
void printCustomer();
void flushLine();
float calcMonthlyPayment(float, int);
int main(void)
{
char input;
for(;;)
{
printf("\n\nChoose From the Options Below:\n");
printf("Type 'N' to Add a New Customer\n");
printf("Type 'P' to Print a Customer's Information\n");
printf("Type 'Q' to Quit the Program\n\n");
scanf(" %c", &input);
flushLine();
switch(toupper(input))
{
case 'N':
addCustomer();
break;
case 'P':
printCustomer();
break;
case 'Q':
exit(0);
default:
printf("Invalid Entry. Please Reenter.\n");
break;
}
}
}
void addCustomer()
{
struct person *cur, *prev, *new_node;
new_node = malloc(sizeof(struct person));
if(new_node == NULL)
{
printf("The Database is Full. You Cannot Add a New Customer.");
return;
}
printf("\nEnter the Customer ID: ");
scanf("%d", &new_node->custID);
flushLine();
while((new_node->custID <= 0) || (new_node->custID > MAX_CUST))
{
printf("Invalid Entry. The Customer ID must be Numeric and Below %d.\n", MAX_CUST);
printf("\nEnter the Customer ID: ");
scanf("%d", &new_node->custID);
flushLine();
}
for(cur = customer, prev = NULL; cur != NULL && new_node->custID > cur->custID; prev = cur, cur = cur->next)
{
continue;
}
if(cur != NULL && new_node->custID == cur->custID)
{
printf("This Customer ID Already Exists\n");
free(new_node);
return;
}
printf("\nEnter Customer's First Name: ");
scanf("%40s", new_node->fName);
flushLine();
printf("\nEnter Customer's Last Name: ");
scanf("%40s", new_node->lName);
flushLine();
printf("\nEnter Customer's Street Address: ");
scanf("%40s", new_node->address);
flushLine();
printf("\nEnter Customer's City: ");
scanf("%40s", new_node->city);
flushLine();
printf("\nEnter Customer's 2-Digit State: ");
scanf("%2s", new_node->state);
flushLine();
printf("\nEnter Customer's 5-Digit Zip Code: ");
scanf("%5s", new_node->zip);
flushLine();
printf("\nEnter the Customer's Principal: ");
scanf("%f", &new_node->principal);
flushLine();
while((new_node->principal < MIN_PRIN) || (new_node->principal > MAX_PRIN))
{
printf("Invalid Entry. The Customer's Principal must be Between %d and %d.\n", MIN_PRIN, MAX_PRIN);
printf("\nEnter Customer's Principal: ");
scanf("%f", &new_node->principal);
flushLine();
}
printf("\nEnter the Customer's Loan Term (In Years): ");
scanf("%d", &new_node->yearlyTerm);
flushLine();
while((new_node->yearlyTerm < MIN_TERM) || (new_node->yearlyTerm > MAX_TERM))
{
printf("Invalid Entry. The Loan Term must be Between %d and %d.\n", MIN_TERM, MAX_TERM);
printf("\nEnter the Customer's Loan Term (In Years): ");
scanf("%d", &new_node->yearlyTerm);
flushLine();
}
calcMonthlyPayment(new_node->principal, new_node->yearlyTerm);
printf("Payment Test in Adding: $%.2f", payment);
new_node->monthlyPayment = payment;
//calcActualPayment();
//new_node->actualPayment = ap;
new_node->next = cur;
if (prev == NULL)
{
customer = new_node;
}
else
{
prev->next = new_node;
}
}
struct person *findCustomer(int custID)
{
struct person *p;
for(p = customer; p != NULL && custID > p->custID; p = p->next)
{
continue;
}
if (p != NULL && custID == p->custID)
{
return p;
}
else
{
return NULL;
}
}
void printCustomer()
{
int custID;
struct person *p;
printf("Enter Customer ID: ");
scanf("%d", &custID);
flushLine();
p = findCustomer(custID);
if(p != NULL)
{
printf("\nCustomer ID:\t\t%d", p->custID);
printf("\nCustomer's Name:\t%s %s", p->fName, p->lName);
printf("\nCustomer's Address:\t%s", p->address);
printf("\n\t\t\t%s, %s %s", p->city, p->state, p->zip);
printf("\nCustomer's Principal:\t$%.2f", p->principal);
printf("\nCustomer's Loan Term:\t%d", p->yearlyTerm);
printf("\nMonthly Payment:\t%.2f", p->monthlyPayment);
}
else
{
printf("The Customer ID Wasn't Found.\n");
}
}
float calcMonthlyPayment(float principal, int yearlyTerm)
{
int monthlyTerm = yearlyTerm * 12;
float monthlyIR = INTEREST / 12;
float payment = principal * monthlyIR * (pow(1 + monthlyIR, monthlyTerm) / (pow(1 + monthlyIR, monthlyTerm)-1));
printf("\nPayment Test in Calculating: $%.2f\n", payment);
return payment;
}
void flushLine()
{
int c;
while((c = getchar()) != EOF && c != '\n')
{
continue;
}
}
person.h文件:
// Program Contstants
#define CHAR_LEN 40
struct person
{
int custID;
char fName[CHAR_LEN + 1];
char lName[CHAR_LEN + 1];
char address[CHAR_LEN + 1];
char city[CHAR_LEN + 1];
char state[3];
char zip[6];
float principal;
int yearlyTerm;
float monthlyPayment;
float actualPayment;
struct person *next;
};
答案 0 :(得分:2)
calcMonthlyPayment()
函数声明一个名为payment
的局部变量,隐藏具有相同名称的全局变量。无论如何,全局变量都是一个坏主意,最好将编写调用函数的代码编写为:
payment = calcMonthlyPayment(new_node->principal, new_node->yearlyTerm);