Question

在Spark 1.6.0中，我有一个数据框，其中包含一个包含作业描述的列，如：

Description
bartender
bartender
employee
taxi-driver
...

我从该列检索一个唯一值列表：

val jobs = people.select("Description").distinct().rdd.map(r => r(0).asInstanceOf[String]).repartition(4)

然后，我尝试为每个职位描述检索具有该职位的人并做一些事情，但我得到一个NullPointerException：

jobs.foreach { 
  ajob => 
   var peoplewithjob = people.filter($"Description" === ajob)
   // ... do stuff
}

我不明白为什么会发生这种情况，因为每个工作都是从人员数据框中提取出来的，所以应该至少有一个人从事这项工作......任何暗示都更受欢迎！这是堆栈跟踪：

Exception in thread "main" org.apache.spark.SparkException: Job aborted due to stage failure: Task 3 in stage 4.0 failed 1 times, most recent failure: Lost task 3.0 in stage 4.0 (TID 206, localhost): java.lang.NullPointerException
at org.apache.spark.sql.DataFrame.<init>(DataFrame.scala:131)
at org.apache.spark.sql.DataFrame.org$apache$spark$sql$DataFrame$$withPlan(DataFrame.scala:2165)
at org.apache.spark.sql.DataFrame.filter(DataFrame.scala:799)
at jago.Run$$anonfun$main$1.apply(Run.scala:89)
at jago.Run$$anonfun$main$1.apply(Run.scala:82)
at scala.collection.Iterator$class.foreach(Iterator.scala:742)
at scala.collection.AbstractIterator.foreach(Iterator.scala:1194)
at org.apache.spark.rdd.RDD$$anonfun$foreach$1$$anonfun$apply$32.apply(RDD.scala:912)
at org.apache.spark.rdd.RDD$$anonfun$foreach$1$$anonfun$apply$32.apply(RDD.scala:912)
at org.apache.spark.SparkContext$$anonfun$runJob$5.apply(SparkContext.scala:1858)
at org.apache.spark.SparkContext$$anonfun$runJob$5.apply(SparkContext.scala:1858)
at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:66)
at org.apache.spark.scheduler.Task.run(Task.scala:89)
at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:213)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
at java.lang.Thread.run(Thread.java:745)

Answer 1

这是因为Spark不支持嵌套操作或转换。如果你想对从$('.classname').html('<span>' + colors.join('</span><span>') + '</span>');中提取的不同值进行操作，你必须将结果提取给驱动程序并在本地迭代：

DataFrame

根据您作为“做事情”应用的转换类型，简单地// or toLocalIterator jobs.collect.foreach { ajob => var peoplewithjob = people.filter($"Description" === ajob) }并汇总可能是更好的主意：

grouBy

dataframe过滤器给出NullPointerException

1 个答案: