如果我拥有xml文件的所有xpath节点，那么我该如何将它映射到另一个等效的xml文件

Question

foreach ($files as $file) {
    $counter++;
    $rootNode = getXMLRootNode($file);
    $rootNodeArray[$file] = $rootNode; 

    $tag = '/'.$rootNode;

    $xml = simplexml_load_file($file);
    $xmlNodeObject = $xml->xpath($tag);
}

$xmlNodeObject存储xml文件的xpath。

更新

示例xml文件：

<Scenario>
    <scenario_txt>
        <audioText  img_a="Anita_ss.jpg" img_b="Sarah_ss.jpg">
            <text>
                <![CDATA[Sarita is working on a high impact and                          confidential bid for the IT department. Her team is working on tight timelines. To overcome stress, Sarita takes a coffee break with Swati, a friend and colleague.]]>
            </text>
        </audioText>
    </scenario_txt>

    <branching>
        <step stepID="0" stepType="conv" speakerName="a" audioFile="">
            <audioText>
                <text>
                </text>
            </audioText>
        </step>

        <step stepID="1" stepType="conv" speakerName="a" audioFile="step1.mp3" endScenario="false">
            <audioText>
                <text><![CDATA[Hi Sarita! How are you doing? You've been working really hard, lately. Is everything fine? ]]>
                </text>
            </audioText>
        </step>

        <step stepID="2" stepType="conv" speakerName="b" audioFile="step2.mp3">
            <audioText>
                <text><![CDATA[Hi Swati! Yeah, I've been deep into work preparing the proposal for the IT bid.]]>
                </text>
            </audioText>
        </step>

        <step stepID="3" stepType="conv" speakerName="a" audioFile="step3.mp3">
            <audioText>
                <text>
                    <![CDATA[So how is the proposal shaping up?]]>               
                </text>
            </audioText>
        </step>
    </branching>
</Scenario>

我还有另一个与此相同的xml文件，但唯一的区别是它具有其他语言的可查看内容。我想要做的是映射这两个xml文件，以便我可以提取其他xml文件的可查看内容。