Question

我使用以下DDL在heroku上创建了表。

CREATE TABLE IF NOT EXISTS "Team"(
  "id" SERIAL,
  "name" varchar(50) NOT NULL,
  "description" varchar(255)
);


CREATE TABLE IF NOT EXISTS  "Member"(
  "id" SERIAL,
  "name" varchar(50) NOT NULL,
  "emp_number" integer NOT NULL,
  "position" varchar(100) NOT NULL,
  "team_id" integer references "Team"("id")
);

我收到以下错误：

    play.api.UnexpectedException: Unexpected exception[ProvisionException: Unable to provision, see the following errors:

1) Error injecting constructor, javax.persistence.PersistenceException: Unable to execute JPA schema generation create command [CREATE TABLE IF NOT EXISTS "Team"(]
  at play.db.jpa.DefaultJPAApi$JPAApiProvider.<init>(DefaultJPAApi.java:35)
  at play.db.jpa.DefaultJPAApi$JPAApiProvider.class(DefaultJPAApi.java:30)
  ...

1 error]
    at play.api.http.DefaultHttpErrorHandler.onServerError(HttpErrorHandler.scala:191) ~[com.typesafe.play.play_2.11-2.4.2.jar:2.4.2]
    at play.api.http.HttpErrorHandlerExceptions$.throwableToUsefulException(HttpErrorHandler.scala:261) ~[com.typesafe.play.play_2.11-2.4.2.jar:2.4.2]
    at play.api.GlobalSettings$class.onError(GlobalSettings.scala:179) [com.typesafe.play.play_2.11-2.4.2.jar:2.4.2]
    ...
Caused by: com.google.inject.ProvisionException: Unable to provision, see the following errors:

1) Error injecting constructor, javax.persistence.PersistenceException: Unable to execute JPA schema generation create command [CREATE TABLE IF NOT EXISTS "Team"(]
  at play.db.jpa.DefaultJPAApi$JPAApiProvider.<init>(DefaultJPAApi.java:35)
  ...

1 error
    at com.google.inject.internal.InjectorImpl$2.get(InjectorImpl.java:1025) ~[com.google.inject.guice-4.0.jar:na]
    at com.google.inject.internal.InjectorImpl.getInstance(InjectorImpl.java:1051) ~[com.google.inject.guice-4.0.jar:na]
    ...
Caused by: javax.persistence.PersistenceException: Unable to execute JPA schema generation create command [CREATE TABLE IF NOT EXISTS "Team"(]
    at org.hibernate.jpa.internal.schemagen.GenerationTargetToDatabase.acceptCreateCommands(GenerationTargetToDatabase.java:64) ~[org.hibernate.hibernate-entitymanager-4.3.9.Final.jar:4.3.9.Final]
    ...
Caused by: org.postgresql.util.PSQLException: ERROR: syntax error at end of input
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:850) ~[org.hibernate.hibernate-entitymanager-4.3.9.Final.jar:4.3.9.Final]
    ...
  Position: 35
    at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2270) ~[org.postgresql.postgresql-9.4-1201-jdbc41.jar:9.4]
    at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:1998) ~[org.postgresql.postgresql-9.4-1201-jdbc41.jar:9.4]
    ...

错误很明显。 SQL包含错误。我对postgres sql很新。至少我知道heroku使用的当前版本支持if not exists语法，但我不确定我哪里出错了。

有人擅长PostgreSQL吗？

Answer 1

如果您直接运行此查询，则会收到错误：

错误：没有唯一约束匹配引用表“Team”的给定键

这为您提供了一个线索，即缺少某些内容可以唯一地标识“Team”表中的列。您已声明表的id是连续的，但忘记添加主键约束。添加它，将允许您执行查询：

CREATE TABLE IF NOT EXISTS "Team"(
    "id" SERIAL primary key,
    ...
);

CREATE TABLE IF NOT EXISTS  "Member"(
    "id" SERIAL primary key,
    ...
);

如果不存在，PostgreSQL 9.4创建表

1 个答案: