Question

我在数据帧中有一个列，其中包含24小时格式的开始时间和结束时间，在使用to_datetime转换后我希望得到开始时间和结束时间之间的差值，但是如果开始时间是23:00且结束时间是00:00然后它给-1天，所以我想做00:00到24:00而不是delta。

我有

s1 = pd.Series(['02/18/2016', '23:00:00', '00:00:00'])

df = pd.DataFrame([list(s1)],  columns =  ["Date", "Start_Time", "End_Time"])

>>> df
Date       Start_Time   End_Time
02/18/2016  23:00:00    00:00:00

必需的输出

Date        Start_Time   End_Time  Diff
02/18/2016  23:00:00     00:00:00  01:00:00

Answer 1

查找End_Time等于'00:00:00'的所有行，并将其转换为+1 days的Timedelta：

df['Diff'] = pd.to_timedelta((df['End_Time'] == '00:00:00').astype(int), unit='d')
# 0   1 days
# Name: End_Time, dtype: timedelta64[ns]

然后将Start_Time和End_Time转换为日期：

for col in ['Start_Time', 'End_Time']:
    df[col] = pd.to_datetime(df['Date'] + ' ' + df[col])

如果End_Time使用等于'00:00:00'，则将df['End_Time'] += df['Diff']增加1天：

Diff

现在您可以照常计算df['Diff'] = df['End_Time'] - df['Start_Time']：

import numpy as np
import pandas as pd

df = pd.DataFrame([['02/18/2016', '23:00:00', '00:00:00']], 
                  columns = ["Date", "Start_Time", "End_Time"]) 

df['Diff'] = pd.to_timedelta((df['End_Time'] == '00:00:00').astype(int), unit='d')
for col in ['Start_Time', 'End_Time']:
    df[col] = pd.to_datetime(df['Date'] + ' ' + df[col])
df['End_Time'] += df['Diff']
df['Diff'] = df['End_Time'] - df['Start_Time']
print(df)

         Date          Start_Time   End_Time     Diff
0  02/18/2016 2016-02-18 23:00:00 2016-02-19 01:00:00

产量

target

如何在python中将时间从00:00转换为24:00

1 个答案: