Question

我正在尝试从设备的联系人中获取多个电话号码。

如果联系人只有一个号码，它可以正常工作，但是当他们有多个号码时它会正常工作（这意味着我会得到＆＃34; \ U00a＆＃34;在数字之间）。

我尝试了所有我能想到的解决方案，但它仍然没有用。

ABMultiValueRef phonesRef = ABRecordCopyValue(person, kABPersonPhoneProperty);
for (int i = 0; i < ABMultiValueGetCount(phonesRef); i++) {
    CFStringRef currentPhoneLabel = ABMultiValueCopyLabelAtIndex(phonesRef, i);
    CFStringRef currentPhoneValue = ABMultiValueCopyValueAtIndex(phonesRef, i);

    if (CFStringCompare(currentPhoneLabel, kABPersonPhoneMobileLabel, 0) == kCFCompareEqualTo) {
        [contactInfoDict setObject:(__bridge NSString *) currentPhoneValue forKey:@"mobileNumber"];
    }

    else if (CFStringCompare(currentPhoneLabel, kABHomeLabel, 0) == kCFCompareEqualTo) {
        [contactInfoDict setObject:(__bridge NSString *) currentPhoneValue forKey:@"homeNumber"];
    }

    CFRelease(currentPhoneLabel);
    CFRelease(currentPhoneValue);
}

Answer 1

您可以使用Contacts Framework。希望这能为您提供直接的联系方式。

#import <Contacts/Contacts.h>

-(void)getContact{
 CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {

    // make sure the user granted us access

    if (!granted) {
        dispatch_async(dispatch_get_main_queue(), ^{
            // user didn't grant access;
            // so, again, tell user here why app needs permissions in order  to do it's job;
            // this is dispatched to the main queue because this request could be running on background thread
        });
        return;
    }

    // build array of contacts

    NSMutableArray *contacts = [NSMutableArray array];

    NSError *fetchError;
    CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactEmailAddressesKey, CNContactPhoneNumbersKey, CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPostalAddressesKey]];

    BOOL success = [store enumerateContactsWithFetchRequest:request error:&fetchError usingBlock:^(CNContact *contact, BOOL *stop) {
        [contacts addObject:contact];
    }];
    if (!success) {
        CTLog(@"error = %@", fetchError);
    }
    __weak typeof(self)weakSelf = self;
    [weakSelf parseContactWithContact:contacts];
}];

- (void)parseContactWithContact :(NSMutableArray* )contacts{
for (CNContact *contact in contacts)
{
    NSString * firstName =  contact.givenName;
    NSString * lastName =  contact.familyName;
    NSString *StrContactName = [NSString stringWithFormat:@"%@ %@",firstName,lastName];
    NSArray * arryPhone = [[contact.phoneNumbers valueForKey:@"value"] valueForKey:@"digits"];

    for (int i=0; i<[arryPhone count]; i++)
    {
        NSMutableDictionary *mDictValue = [[NSMutableDictionary alloc]init];
        [mDictValue setValue:firstName forKey:@"firstName"];
        [mDictValue setValue:lastName forKey:@"lastName"];
        [mDictValue setValue:StrContactName forKey:@"contactName"];
        [mDictValue setValue:[arryPhone objectAtIndex:i] forKey:@"Phone"];
        [arrayOfContacts addObject:mDictValue];
    }
}

获取\ U00a，从iOS联系人

1 个答案: