Question

现在我正在构建一个应用程序。我已经设置了一个将多个图像上传到数据库的表单。这是我的简单代码

查看

<?php echo form_open_multipart('admin/product/post'); ?>
<table class="table table-stripped">
    <tbody>
        <tr>
            <td>Code</td>
            <td>
                <?php echo form_input(array('class'=>'form-control','name'=>'kodeproduk')); ?>                                  
            </td>
        </tr>
        <tr>
            <td>Display</td>
            <td>
                <input class="form-control" type="file" name="userfile[]" id="multiple" multiple="" />    
            </td>
        </tr>
        <tr>
            <td>Description</td>
            <td>
                <div class="textarea textarea-editor">
                    <textarea name="ket" cols="50" rows="5" class="form-control"></textarea>
                </div>                                  
            </td>
        </tr>
        <tr>
            <td colspan="2">
                <button type="submit" class="btn btn-primary btn-outline btn-block pull-right"><span>Save</span></button>
            </td>
        </tr>
    </tbody>
</table>
<?php echo form_close(); ?>

控制器

public function post(){        
    if($this->_validation()===FALSE){ 
        $this->session->set_flashdata('error', 'Ooops, there was an error');
        redirect(base_url("admin/product"));
    }else{
        $files = $_FILES;
        $cpt = count($_FILES['userfile']['name']);
            for($i=0; $i<$cpt; $i++){
            $_FILES['userfile']['name']= $files['userfile']['name'][$i];
            $_FILES['userfile']['type']= $files['userfile']['type'][$i];
            $_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
            $_FILES['userfile']['error']= $files['userfile']['error'][$i];
            $_FILES['userfile']['size']= $files['userfile']['size'][$i];
            $this->upload->initialize($this->set_upload_options());
            $this->upload->do_upload();
            $fileName = $_FILES['userfile']['name'];
            $images[] = $fileName;
        }
        $fileName = implode(',',$images);

        $data = array(  'kodeProduk'                => $this->input->post('kodeproduk'),
                        'ket'                       => $this->input->post('ket'),

                        'GambarBesar'               => $fileName
        );

        unset($data['submit']);                             
        $this->table->add_record($data);
        $this->session->set_flashdata('success', 'Product has been saved.');
        redirect(base_url("admin/product"));
    }   
}

模型

public function add_record($data){
    $this->db->insert('produk', $data);
    return;
}

当我发布它时，我遇到了一个问题，所有图像文件都上传到服务器上的目录，但实际上只有一个图像作为一行存储在MySQL表中。那么如何修复我的代码呢？谢谢提前

Answer 1

好的一些小改动可能会有所帮助

public function post(){        
    if($this->_validation()===FALSE){ 
        $this->session->set_flashdata('error', 'Ooops, there was an error');
        redirect(base_url("admin/product"));
    }else{
        $files = $_FILES;
        $images = array();
        $cpt = count($_FILES['userfile']['name']);
            for($i=0; $i<$cpt; $i++){
            $_FILES['userfile']['name']= $files['userfile']['name'][$i];
            $_FILES['userfile']['type']= $files['userfile']['type'][$i];
            $_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
            $_FILES['userfile']['error']= $files['userfile']['error'][$i];
            $_FILES['userfile']['size']= $files['userfile']['size'][$i];
            $this->upload->initialize($this->set_upload_options());
            $this->upload->do_upload();
            $images[] = $_FILES['userfile']['name'];
        }
        $fileName = implode(',',$images);

        $data = array(  'kodeProduk'                => $this->input->post('kodeproduk'),
                        'ket'                       => $this->input->post('ket'),

                        'GambarBesar'               => $fileName
        );

        unset($data['submit']);                             
        $this->table->add_record($data);
        $this->session->set_flashdata('success', 'Product has been saved.');
        redirect(base_url("admin/product"));
    }   
}

Answer 2

请尝试此代码我希望这是解决

ArrayAdapter

使用Codeigniter进行多个图像上传仅保存一个到MySQL数据库的文件路径

2 个答案: