Question

我插入多个表，需要从最后一个插入到表1中获取ID，并将其用作表2插入中的变量。

ID会自动递增。

在表单中单击提交按钮后，将运行查询。

查询＆＃39; S：

$sql = "INSERT INTO table1 (Text) VALUES ($T1text);";
$sql = "INSERT INTO table2 (table1ID,Text) VALUES ($table1id, $T2text);";


table1 {id,Text}
table2 {id,table1.id,Text}

Answer 1

有一个PHP函数（Decprecated，7.0中删除！）或者根据mysql / mysqli / pdo函数。

解决方案

PHP（已弃用）

实施例

$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
 die('Could not connect: ' . mysql_error());
}
mysql_select_db('mydb');

mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysql_insert_id());

来源：http://php.net/manual/en/function.mysql-insert-id.php

Mysql / Mysqli / PDO

的mysqli $ sql =＆＃34; INSERT INTO MyGuests（firstname，lastname，email）价值观（＆＃39; John＆＃39;，＆＃39; Doe＆＃39;，＆＃39; john@example.com'）＆＃34 ;;

if (mysqli_query($conn, $sql)) {
    $last_id = mysqli_insert_id($conn);
    echo "New record created successfully. Last inserted ID is: " . $last_id;
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

PDO

$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john@example.com')";
// use exec() because no results are returned
$conn->exec($sql);
$last_id = $conn->lastInsertId();

来源：http://www.w3schools.com/php/php_mysql_insert_lastid.asp

从上次插入到表中获取ID

1 个答案: