如何在clojure中获得`doc`函数的输出？

Question

我试图保存$_term->getSubCategory();函数的输出，例如：

doc

但是，user> (def doc-str-split (doc str/split)) ------------------------- clojure.string/split ([s re] [s re limit]) Splits string on a regular expression. Optional argument limit is the maximum number of splits. Not lazy. Returns vector of the splits. #'user/doc-str-split user> doc-str-split nil user> 获得了nil。我试图获得doc-str-split输出的type：

doc

仍然获得user> (type (doc str/split)) ------------------------- clojure.string/split ([s re] [s re limit]) Splits string on a regular expression. Optional argument limit is the maximum number of splits. Not lazy. Returns vector of the splits. nil 。如何保存nil函数的输出？

Answer 1

您可以使用with-out-str来捕获输出，如下所示：

user> (def doc-str-split (with-out-str (doc str/split)))
#'user/doc-str-split

user> (println doc-str-split)
-------------------------
clojure.string/split
([s re] [s re limit])
  Splits string on a regular expression.  Optional argument limit is
  the maximum number of splits. Not lazy. Returns vector of the splits.

nil

user> (type (with-out-str (doc str/split)))
java.lang.String

Answer 2

你可以像这样获得doc字符串：

user.core=> (def doc (prn (:doc (meta #'clojure.string/split))))
"Splits string on a regular expression.  Optional argument limit is  
 the maximum number of splits. Not lazy. Returns vector of the splits."