Question

我需要合并两个具有以下格式的数组：

array(9) 
{ 
[0]=> array(1) { ["BLA"]=> string(7) "bis 050" } 
[1]=> array(1) { ["BLA"]=> string(7) "bis 060" } 
[2]=> array(1) { ["BLA"]=> string(7) "bis 070" } 
[3]=> array(1) { ["BLA"]=> string(7) "bis 080" } 
[4]=> array(1) { ["BLA"]=> string(7) "bis 090" } 
[5]=> array(1) { ["BLA"]=> string(7) "bis 100" } 
[6]=> array(1) { ["BLA"]=> string(7) "bis 110" } 
[7]=> array(1) { ["BLA"]=> string(7) "bis 120" } 
[8]=> array(1) { ["BLA"]=> string(6) "gr 120" } 
} 

array(5) 
{ 
[0]=> array(2) {
   ["BLA"]=> string(7) "bis 050" 
   ["Amount"]=> string(3) "832" } 
[1]=> array(2) { 
   ["BLA"]=> string(7) "bis 060" 
   ["Amount"]=> string(3) "448" } 
[2]=> array(2) { 
   ["BLA"]=> string(7) "bis 090" 
   ["Amount"]=> string(4) "1216" } 
[3]=> array(2) { 
   ["BLA"]=> string(7) "bis 100" 
   ["Amount"]=> string(4) "1024" } 
[4]=> array(2) { 
   ["BLA"]=> string(7) "bis 110" 
   ["Amount"]=> string(3) "896" } 
}

我尝试了array_merge()和array_merge_recursive()，但它不起作用。我的目标是将第二个键及其值从array2（Amount）写入数组1，其中第一个键（BLA）的值相同。另外，如果array2中没有对应的值，我想写"Amount":"0"。有没有办法用PHP做到这一点？

结果应如下所示：

    Result:
{ 
[0]=> array(2) { 
   ["BLA"]=> string(7) "bis 050"  
   ["Amount"]=> string(3) "832" } 
[1]=> array(2) { 
   ["BLA"]=> string(7) "bis 060"  
   ["Amount"]=> string(3) "448" } 
[2]=> array(2) { 
   ["BLA"]=> string(7) "bis 070" 
   ["Amount"]=> string(1) "0" }  
[3]=> array(2) { 
   ["BLA"]=> string(7) "bis 080" 
   ["Amount"]=> string(1) "0" }  
[4]=> array(2) { 
   ["BLA"]=> string(7) "bis 090" 
   ["Amount"]=> string(4) "1216" }
[5]=> array(2) { 
   ["BLA"]=> string(7) "bis 100" 
   ["Amount"]=> string(4) "1024" }  
[6]=> array(2) { 
   ["BLA"]=> string(7) "bis 110" 
   ["Amount"]=> string(3) "896" } 
[7]=> array(2) { 
   ["BLA"]=> string(7) "bis 120" 
   ["Amount"]=> string(1) "0" }  
[8]=> array(2) { 
   ["BLA"]=> string(6) "gr 120" 
   ["Amount"]=> string(1) "0" } 
}

Answer 1

我整理了一个快速演示，似乎可以解决您的问题。如果您需要任何其他帮助，请告诉我。

<?php

$arrOne = array(
    array("BLA" => "bis 050"),
    array("BLA" => "bis 060"),
    array("BLA" => "bis 070"),
    array("BLA" => "bis 080"),
    array("BLA" => "bis 090"),
    array("BLA" => "bis 100"),
    array("BLA" => "bis 110"),
    array("BLA" => "bis 120"),
    array("BLA" => "gr 120")
);

$arrTwo = array(
    array("BLA" => "bis 050","Amount" => "832"),
    array("BLA" => "bis 060","Amount" => "448"),
    array("BLA" => "bis 090","Amount" => "1216"),
    array("BLA" => "bis 100","Amount" => "1024"),
    array("BLA" => "bis 110","Amount" => "896")
);


$arrOutput = array();

foreach($arrOne as $arrOneValue) {
    $searchKey = $arrOneValue["BLA"];

    foreach($arrTwo as $arrTwoValue) {
        if($arrTwoValue["BLA"] == $searchKey) {
            $arrOutput[] = array("BLA" => $searchKey, "Amount" => $arrTwoValue["Amount"]);
            continue 2; // Continue the outer loop
        }
    }

    // We didn't find the key
    $arrOutput[] = array("BLA" => $searchKey, "Amount" => "0");
}

var_dump($arrOutput);
?>

产生如下内容：

array(9) { 
    [0]=> array(2) { ["BLA"]=> string(7) "bis 050" ["Amount"]=> string(3) "832" } 
    [1]=> array(2) { ["BLA"]=> string(7) "bis 060" ["Amount"]=> string(3) "448" } 
    [2]=> array(2) { ["BLA"]=> string(7) "bis 070" ["Amount"]=> string(1) "0" } 
    [3]=> array(2) { ["BLA"]=> string(7) "bis 080" ["Amount"]=> string(1) "0" } 
    [4]=> array(2) { ["BLA"]=> string(7) "bis 090" ["Amount"]=> string(4) "1216" } 
    [5]=> array(2) { ["BLA"]=> string(7) "bis 100" ["Amount"]=> string(4) "1024" } 
    [6]=> array(2) { ["BLA"]=> string(7) "bis 110" ["Amount"]=> string(3) "896" } 
    [7]=> array(2) { ["BLA"]=> string(7) "bis 120" ["Amount"]=> string(1) "0" } 
    [8]=> array(2) { ["BLA"]=> string(6) "gr 120" ["Amount"]=> string(1) "0" } 
}

Answer 2

您可以尝试这种方式：

$result = array_filter($array1, function (&$item) {
    $item['Amount'] = '0';
    return $item;
});

$index = array_column( $result,'BLA' );
foreach( $array2 as $row )
{
    $found = array_search( $row['BLA'], $index );
    if( $found === False )
    {
        $result[] = $row;
        $index[]  = $row['BLA'];
    }
    else
    {
        $result[$found]['Amount'] = $row['Amount'];
    }
}

print_r( $result );

的 eval.in demo

首先，我过滤数组1以向每个元素添加空Amount;然后我创建一个BLA值的索引，以避免嵌套foreach循环。通过第二个数组的foreach循环，我发现密钥是否存在于修改过的数组中：如果它们存在，我会更改“数量”数字。键，否则我将一个新项添加到数组。

通过这种方法，您只执行两个foreach循环（将array_filter视为foreach，三个也考虑array_column）; whit嵌套foreach，相反，你必须执行可变数量的循环，如果你有大型数组，会影响性能。

请注意：

array_column在php＆gt; = 5.5中可用。

如果您使用以前的版本，则必须将相应的行替换为：

$index = array(); foreach( $result as $row ) $index[] = $row['BLA'];

Answer 3

试试这个：

$array1 = '[
{"BLA":"bis 050"},
{"BLA":"bis 060"},
{"BLA":"bis 070"},
{"BLA":"bis 080"},
{"BLA":"bis 090"},
{"BLA":"bis 100"},
{"BLA":"bis 110"},
{"BLA":"bis 120"},
{"BLA":"gr 120"}
]';

$array2 = '[
{"BLA":"bis 050","Amount":"832"},
{"BLA":"bis 060","Amount":"448"},
{"BLA":"bis 090","Amount":"1216"},
{"BLA":"bis 100","Amount":"1024"},
{"BLA":"bis 110","Amount":"896"}
]';

$a1 = json_decode($array1, TRUE);
$a2 = json_decode($array2, TRUE);
$result = [];

foreach ($a1 as $source) {
  $found = FALSE;
  foreach ($a2 as $key => $content) {
    if ($content['BLA'] == $source['BLA']) {
      $element = $content;
      $a2[$key]['BLA'] = NULL; // ensure not to reuse furtherly
      $found = TRUE;
      break;
    }
  }
  if (!$found) {
    $element = ['BLA' => $source['BLA'], 'Amount' => 0];
  }
  $result[] = $element;
}
// add unused $a2 content, if any
if ($a2) {
  $result += $a2;
}

echo '<pre>' . print_r(str_replace(",{", ",\n{", json_encode($result)), TRUE) . '</pre>';

在PHP中合并具有不同长度的多维数组

3 个答案:

请注意：