Question

我正在使用此lib作为标签栏：link 根据图片，我使用它，它的工作原理，但有一个问题，我应该在另一个视图寻呼机使用视图寻呼机，它会产生一些问题，如你在图片中看到的。我该如何解决？

A Screen shot from my app and the problem

编辑：这是我的代码

public void drive(double distance){
    double fuelUsed = distance / milesPerGallon;
    fuel = fuel - fuelUsed;
}

}

此代码用于第一个标签栏

MainActivity.js


public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    FragmentPagerItemAdapter adapter = new FragmentPagerItemAdapter(
            getSupportFragmentManager(), FragmentPagerItems.with(this)
            .add("1111", PageFragment.class)
            .add("222", PageFragment.class)
            .add("33333", PageFragment.class)
            .add("444", PageFragment.class)
            .create());

    ViewPager viewPager = (ViewPager) findViewById(R.id.viewpager);
    viewPager.setAdapter(adapter);

    SmartTabLayout viewPagerTab = (SmartTabLayout) findViewById(R.id.viewpagertab);
    viewPagerTab.setViewPager(viewPager);
}

这是第二个标签栏片段的代码

PageFragment.js

public class PageFragment extends Fragment {
    @Override
    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container,
                             @Nullable Bundle savedInstanceState) {
        return inflater.inflate(R.layout.fragment_demo, container, false);
    }

    @Override
    public void onViewCreated(View view, @Nullable Bundle savedInstanceState) {
        super.onViewCreated(view, savedInstanceState);
        int position = FragmentPagerItem.getPosition(getArguments());
        FragmentPagerItemAdapter adapter = new FragmentPagerItemAdapter(
                getActivity().getSupportFragmentManager(), FragmentPagerItems.with(getActivity())
                .add("One", TestFragment.class)
                .add("Two", TestFragment.class)
                .add("Three", TestFragment.class)
                .add("Four", TestFragment.class)
                .add("Five", TestFragment.class)
                .add("Six", TestFragment.class)

                .create());

        ViewPager viewPager = (ViewPager) view.findViewById(R.id.viewpager2);
        viewPager.setAdapter(adapter);

        SmartTabLayout viewPagerTab = (SmartTabLayout) view.findViewById(R.id.viewpagertab2);
        viewPagerTab.setViewPager(viewPager);
    }
}

Answer 1

使用getChildFragmentManager()类而不是

解决了问题

 getActivity().getSupportFragmentManager()

PageFragment.js 文件

中的

Answer 2

你可能会被拒绝投票，因为你没有努力自己解决这个问题，或者你没有得到你的发现！

但是，我最近实现了这个，它适用于我的情况。它在一个活动中有两个选项卡（作为两个片段）。

代码如下。

<强> MainActivity：

public class MainActivity extends AppCompatActivity {

TabLayout.Tab Tab1,Tab2;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
    setSupportActionBar(toolbar);

    final TabLayout tabLayout = (TabLayout) findViewById(R.id.tab_layout);
    Tab1 = tabLayout.newTab().setText("Monthly Expenses");
    Tab2 = tabLayout.newTab().setText("Daily Expenses");

    tabLayout.addTab(Tab1);
    tabLayout.addTab(Tab2);
    tabLayout.setTabGravity(TabLayout.GRAVITY_FILL);

    final ViewPager viewPager = (ViewPager) findViewById(R.id.pager);
    final PagerAdapter adapter = new PagerAdapter(getSupportFragmentManager(),tabLayout.getTabCount());
    viewPager.setAdapter(adapter);
    viewPager.addOnPageChangeListener(new TabLayout.TabLayoutOnPageChangeListener(tabLayout));
    tabLayout.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
        @Override
        public void onTabSelected(TabLayout.Tab tab) {
            viewPager.setCurrentItem(tab.getPosition());
        }

        @Override
        public void onTabUnselected(TabLayout.Tab tab) {

        }

        @Override
        public void onTabReselected(TabLayout.Tab tab) {

        }
    });
}
}

PagerAdapter.java：

public class PagerAdapter extends FragmentStatePagerAdapter
{
int NumOfTabs;
public PagerAdapter (FragmentManager fm, int NumberOfTabs)
{
    super(fm);
    this.NumOfTabs = NumberOfTabs;
}

@Override
public Fragment getItem(int position)
{
    switch (position)
    {
        case 0:
            TabFragment1 tab1 = new TabFragment1();
            return tab1;

        case 1:
            TabFragment2 tab2 = new TabFragment2();
            return tab2;

        default:
            return null;
    }
}

public int getCount()
{
    return NumOfTabs;
}
}

TabFragment1.java：

public class TabFragment1 extends Fragment{
FloatingActionButton fab;
MyBaseAdapter baseAdapter;
static ArrayList<ListRowItem> listitem = new ArrayList<>();
ListView listView;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    return inflater.inflate(R.layout.tab_fragment_1, container, false);
}
}

TabFragment2.java：

public class TabFragment2 extends Fragment{
FloatingActionButton fab;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    return inflater.inflate(R.layout.tab_fragment_2, container, false);
}
}

希望这就是你要找的东西！

如何在一个Activity中使用两个标签栏（和查看寻呼机）？

2 个答案: