Question

我是java的初学者。在做这个简单的程序时（程序很长，请不要介意）我发现：

这不起作用。

import java.util.*;
class store
{
    store()
    {
        System.out.println("RESLUTS OF STUDENTS");
        System.out.println();
    }
    void stu1 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu2 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu3 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu4 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu5 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
}
class stu
{
    public static void main(String[] args) {
        Scanner v = new Scanner (System.in);
        System.out.println("Enter the name of first student");
        String p = v.nextLine();
        System.out.println("Enter the marks for first student");
        int q = v.nextInt();
        System.out.println("Enter the name of second student");
        String r = v.nextLine();
        System.out.println("Enter the marks for second student");
        int s = v.nextInt();
        System.out.println("Enter the name of third student");
        String t = v.nextLine();
        System.out.println("Enter the marks for third student");
        int u = v.nextInt();
        System.out.println("Enter the name of fourth student");
        String w = v.nextLine();
        System.out.println("Enter the marks for fourth student");
        int x = v.nextInt();
        System.out.println("Enter the name of fifth student");
        String y = v.nextLine();
        System.out.println("Enter the marks for fifth student");
        int z = v.nextInt();
        store st = new store ();
        st.stu1(p,q);
        st.stu2(r,s);
        st.stu3(t,u);
        st.stu4(w,x);
        st.stu5(y,z);   
    }
}

但是这样做.sextLine（）和nextInt（）与print语句分开。

import java.util.*;
class store
{
    store()
    {
        System.out.println("RESLUTS OF STUDENTS");
        System.out.println();
    }
    void stu1 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu2 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu3 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu4 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
    void stu5 (String name,int marks)
    {
        System.out.println("The name of student is : "+ name+"  and he got :"+marks+"marks");
    }
}
class stu
{
    public static void main(String[] args) {
        Scanner v = new Scanner (System.in);
        System.out.println("Enter the name of first student");
        String p = v.nextLine();
        System.out.println("Enter the name of second student");
        String r = v.nextLine();
        System.out.println("Enter the name of third student");
        String t = v.nextLine();
        System.out.println("Enter the name of fourth student");
        String w = v.nextLine();
        System.out.println("Enter the name of fifth student");
        String y = v.nextLine();
        System.out.println("Enter the marks for first student");
        int q = v.nextInt();
        System.out.println("Enter the marks for second student");
        int s = v.nextInt();
        System.out.println("Enter the marks for third student");
        int u = v.nextInt();
        System.out.println("Enter the marks for fourth student");
        int x = v.nextInt();
        System.out.println("Enter the marks for fifth student");
        int z = v.nextInt();
        store st = new store ();
        st.stu1(p,q);
        st.stu2(r,s);
        st.stu3(t,u);
        st.stu4(w,x);
        st.stu5(y,z);   
    }
}

这是为什么？是不是基本相同？或者还有其他方法吗？

Answer 1

这是因为Scanner＃nextInt方法不消耗输入的最后一个换行符，因此在下次调用Scanner＃nextLine
时会消耗该换行符

您的问题已在此处得到解答：Scanner is skipping nextLine() after using next(), nextInt() or other nextFoo() methods

使用nextInt（）放置nextLIne（）

1 个答案: