Question

有一个包含网站的表格和一个包含说明的多对一表格试图获取一个列表，首先获取最新的描述，然后按描述的内容显示它们......

在views.py中有以下内容

def category(request, category_name_slug):
    """Category Page"""
    context_dict = {}

    try:
        category = Category.objects.get(slug=category_name_slug)
        subcategory = SubCategory.objects.filter(category=category)
        websites = Website.objects.filter(sub_categories=subcategory,     online=True, banned=False)
        sites = websites
        descriptions =     WebsiteDescription.objects.prefetch_related("about")
        descriptions = descriptions.filter(about__in=sites)
        descriptions = descriptions.order_by('about', '-updated')
        descs = []
        last_site = "" # The latest site selected
        # Select the first (the latest) from each site group
        for desc in descriptions:
            if last_site != desc.about.id:
                last_site = desc.about.id
                desc.url = desc.about.url
                desc.hs_id = desc.about.id
                desc.banned = desc.about.banned
                desc.referral = desc.about.referral
                descs.append(desc)
        context_dict['descs'] = descs
        context_dict['websites'] = websites
        context_dict['subcategory'] = subcategory
        context_dict['category'] = category
    except SubCategory.DoesNotExist:
        pass

    return render(request, 'category.html', context_dict)

这给了我一个包含网站及其最新描述的列表，所以我在category.html中有以下内容

        {% if category %}
        <h1>{{ category.name }}</h1>

{% for subcategory in category.subcategory_set.all %}

             <a href="/links/{{ category.slug }}/{{ subcategory.slug     }}">{{ subcategory.name }}  ({{ subcategory.website_set.all|length }}) </a>

        {% endfor %}

            {% if descs %}
{% load endless %}

{% paginate descs %}
                {% for desc in     descs|dictsortreversed:"description"|dictsortreversed:"officialInfo" %}

                        <ul id='list' class='linksteps'>

        <a href="/{{ desc.about_id }}" rel="nofollow" target="_blank">
        <img src="/static/screenshots/{{ desc.about_id }}.png" />
        </a>

                <li><h3><a href="/{{ desc.about_id }}" rel="nofollow"     target="_blank">{{ desc.about_id }}</a>{% if desc.title %} - {{ desc.title }}     {% endif %}</h3>


          {% if desc.description %}<b>Description: </b>{{     desc.description }}
          <br />{% endif %} {% if desc.subject %}<b>Keywords: </b>{{     desc.subject }}
          <br />{% endif %} {% if desc.type %}<b>Type: </b>{{ desc.type }}
          <br />{% endif %} {% if desc.officialInfo %} {% if     desc.language %}<b>Language: </b>{{ desc.language }}
          <br />{% endif %} {% if desc.contactInformation %}<b>Contact     info: </b>{{ desc.contactInformation }}
          <br />{% endif %}


          {% else %}
          {% endif %}
        </li>


                       </ul>
</div>

                {% endfor %}
 {% show_pages %}
            {% else %}
                <strong>No websites currently in category.</strong>
            {% endif %}
        {% else %}
            The specified subcategory {{ category_name }} does not exist!
        {% endif %}

最初我使用了dictsort

{% for desc in descs|dictsortreversed:"description"|dictsortreversed:"officialInfo"|dictsortreversed:"referral" %}

按所需顺序给我列表，所以我很开心;）然而，我决定我需要一些分页因为列表变得太长了。 django-endless-pagination工作得很好并且做了它应该做的事情，但是在dictsort开始之前它会分开我的列表。

有没有一种方法可以在分页发生之前和在初始查询中我ordered_by之后进行排序以选择最新的描述？

非常有责任

编辑：

没有得到任何答案，所以我的问题可能不明确。

据我所知，我需要在views.py中的context_dict中对值进行排序，以替换模板中的dictsort

解决:::

这样做可以让我替换dictsort。

descs1 = sorted(descs, key=operator.attrgetter('referral', 'officialInfo', 'description'), reverse=True)
context_dict['descs'] = descs1

Answer 1

解决:::

这样做可以让我替换dictsort。

descs1 = sorted(descs, key=operator.attrgetter('referral', 'officialInfo', 'description'), reverse=True)
context_dict['descs'] = descs1

查询后django排序字典

1 个答案: