Question

我有一个使用Django Rest Framework JSON API的django 1.9.2项目：

https://github.com/django-json-api/django-rest-framework-json-api：

我的观点看起来像这样：

class QuestionViewSet(viewsets.ReadOnlyModelViewSet):
    """
    API endpoint that allows questions and answers to be read.
    """
    resource_name = 'questions'
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer
    renderers = renderers.JSONRenderer
    parsers = parsers.JSONParser

典型响应如下：

{"links": {"first": "http://testserver/api/v1/coaches?page=1", "last": "http://testserver/api/v1/coaches?page=1", "next": null, "prev": null}, "results": [{"id": 1, "created": "2016-02-11T02:41:22.569000Z", "updated": null, "deleted": null, "uuid": "0473c709-994f-465b-989e-407c623f365f", "user": {"type": "User", "id": "2"}}, {"id": 2, "created": "2016-02-11T02:41:46.853000Z", "updated": null, "deleted": null, "uuid": "36e19c0e-bda6-4bd7-bc73-374a6fc509d6", "user": {"type": "User", "id": "3"}}, {"id": 3, "created": "2016-02-11T02:42:05.419000Z", "updated": null, "deleted": null, "uuid": "d0798ff4-3be2-4cf3-81ac-edf8049eb075", "user": {"type": "User", "id": "4"}}], "meta": {"pagination": {"page": 1, "pages": 1, "count": 3}}}

我希望输出具有数据属性而不是结果属性。如何告诉DRF JSON API输出此处描述的样式：

http://jsonapi.org/format/

Answer 1

我的问题是我在视图中有一个viewset派生类，如下所示：

class QuestionViewSet(viewsets.ReadOnlyModelViewSet):
    """
    API endpoint that allows questions and answers to be read.
    """
    resource_name = 'questions'
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer
    renderers = renderers.JSONRenderer
    parsers = parsers.JSONParser

错误。渲染器和解析器属性实际上分别是renderer_classes和parser_classes。而且，这些属性的右值是元组，而不是单例。因此：

class QuestionViewSet(viewsets.ReadOnlyModelViewSet):
    """
    API endpoint that allows questions and answers to be read.
    """
    resource_name = 'questions'
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer
    renderer_classes = (renderers.JSONRenderer,)
    parser_classes = (parsers.JSONParser,)

在此更改之后，JSON API响应基本上是正确的：

{"data":{"type":"questions","id":"1","attributes":{"created":"2016-02-10T04:28:50.742000Z","updated":null,"deleted":null,"uuid":"eddfc27d-2677-49e5-bd37-92fecea340bd","text":"Are you dizzy?"},"relationships":{"answers":{"data":[{"type":"Answer","id":"1"},{"type":"Answer","id":"2"},{"type":"Answer","id":"3"}]},"members":{"data":[{"type":"Member","id":"1"},{"type":"Member","id":"2"},{"type":"Member","id":"3"},{"type":"Member","id":"4"}],"meta":{"count":4}}}}}

Answer 2

我相信你必须创建一个自定义渲染器来处理你的项目。以下是rest-framework renderers

的指南

我可以指向json模板的Response类中的行，以获得快速而又脏的修复： Response(), line 35

如何在Django Rest Framework JSON API中生成JSON-API数据属性vs结果属性？

2 个答案: