解决迭代程序的错误

时间:2016-02-11 01:44:39

标签: java iteration

我试图创建一个带有用户输入的迭代程序,从我的这本教科书中复制但是在返回时我不断收到错误:"此行的多个标记 - a的基本类型int没有字段b - 令牌上的语法错误"," ,.预期"

import java.util.Scanner;



public class Code3 {



public static void main (String [] args)
{
    Scanner scanner = new Scanner(System.in);  
    System.out.println("Enter A: ");
    int a = scanner.nextInt(); 
    System.out.println("Enter B: ");
    int b = scanner.nextInt(); 


    if (a==b)
        return;

    if (a>b)
        return (a-b, b);
    else 
        return (a, b-a);
}
}

1 个答案:

答案 0 :(得分:1)

public static void main (String [] args)
{
    Scanner scanner = new Scanner(System.in);  
    System.out.println("Enter A: ");
    int a = scanner.nextInt(); 
    System.out.println("Enter B: ");
    int b = scanner.nextInt(); 

    if (a>b) {
        System.out.println("Results: " + (a-b) + ", " + b);
    } else if(a < b) {
        System.out.println("Results: " + a + ", " + (b-a));
    }
}