我有一个包含一年中12个月的清单X.在我的数据中,我有一个Y列,其中包含以下级别:“完成”,“未完成”和“”。我想用字符串“Unknown”替换“”。
我试过了:
for (i in 1:length(X)) {
X[[i]]$Y[which(is.na(X[[i]]$Y))] == "Unknown"
}
我收到错误:
“错误:意外输入” PList15 [[I]] $ IB.Opportunity.Type [其中(is.na(PList15 [[I]] $ IB.Opportunity))] ==“未知”
答案 0 :(得分:1)
你不需要循环,你可以这样做:
# Some data with `""`
v <- 1:10
v[c(3,5,8)] <- ""
v
[1] "1" "2" "" "4" "" "6" "7" "" "9" "10"
v[v == ""] <- "Unknown"
[1] "1" "2" "Unknown" "4" "Unknown" "6" "7" "Unknown" "9" "10"
答案 1 :(得分:1)
由于Y是一个因素,你可以这样做:
levels(X$Y)[levels(X$Y)==""] <- "unknown"