制作循环以测试值

时间:2016-02-08 06:18:23

标签: java loops

我需要帮助创建一个循环来查看从1到数字1的每个值。 另外如何测试每个值以查看它是否为a 数字的除数,如果是,则将其加到总和中。

这是我到目前为止所做的:

public static void main(String[] args) {
  Scanner input = new Scanner (System.in);

  System.out.print("Please enter a positive integer: ");
  int n = input.nextInt();

  while (n < 0) {
    System.out.println(n + " is not positive.");
    System.out.print("Please enter a positive integer: ");
    n = input.nextInt();
  }
}

2 个答案:

答案 0 :(得分:0)

您可以将其用作应用程序的起始块:

    package Testers;

import java.io.Console;

public class Application {

    public static void main(String[] args)
    {
        Console console = System.console();
        if (console == null) 
        {
            System.err.println("No console.");
            System.exit(1);
        }

        boolean keepRunning = true;
        while (keepRunning)
        {       
            String name =  console.readLine("Type your positive integer");
            try{
            int integer = Integer.parseInt(name);
            if(integer < 0){
                System.out.println("You must specify a positive integer!");
            }
            for(int i = 1; i<integer; i++){ 
                // our variable "i" is smaller than "integer". This will parse all the numbers between one and "integer" -1.
                if(i % 2 == 0){
                    //"i" IS divisible by 2. Of course, you can change this value to what you want to change it to.
                    //Here you can add it to a sum
               }else{
                //"i" is not divisible by 2. Of course, you can change this value to what you want to change it to.
                }
            }
            }catch(NumberFormatException e){
                System.out.println("You must specify a positive integer!");
            }
        }
    }   

}

答案 1 :(得分:0)

如果您想要执行已知次数的操作,最好使用UInt16[] availableRequestedStates = { 2, 3, 4, 6, 7, 8, 9, 10, 11 }; compSystem["AvailableRequestedStates"] = availableRequestedStates; compSystem.Put(); ManagementBaseObject inParams = compSystem.GetMethodParameters("RequestStateChange"); inParams["RequestedState"] = 2; ManagementBaseObject result = compSystem.InvokeMethod("RequestStateChange", inParams, null); 循环。如果您想为for1执行某些操作,则循环可能看起来像

n-1

请注意,它从1开始计数,并在for(int i = 1; i < n; i++) { // do stuff } 大于或等于i时立即停止。

为了知道一个数字(比如n)是否可以被某个数字整除,比如n,可以使用模运算符k。如果%这意味着n % k == 0可以被n整除。使用k语句可以对此进行测试,当您有一些if变量时,您可以添加任何您想要的变量来进行总结。

希望有所帮助