Question

所以我有两个表用户（IDN，RoP）和search_info（IDN，位置，年龄）（IDN - 是一个关键列）我需要收集并计算数据库中具有正确类型（RoP）和正确信息（位置和年龄）的行。

所以php：

$location = $_POST['location'];
$age = $_POST['age'];
$type=$_SESSION['type'];

然后我制作了mysql代码......它不是选择原始数据，而是计算它们。我知道查询不再使用，但我将其用于教育目的。

$search_result= mysql_query("
            SELECT COUNT(a.IDN)
            FROM users AS a LEFT JOIN info_search AS b 
                ON a.IDN = b.IDN  
            Where a.RoP='$s_type' AND b.Location = '$location' AND b.Age = '$age'
    ");
$search=mysql_fetch_array($search_result);

因此，您可以看到代码正在运行，但在这里工作人员。我发送了位置1,2或3，否则为0.所以如果location == 0我想从数据库行中获取而不管位置（换句话说 - 任何位置）。与年龄相似。是否有可能在MYSQL上实现？如何更改MYSQL抓取任何位置的变量？和代码中的最后一个问题。我正在尝试选择需求数据，但输出它们有问题。那么怎么打印出来呢？

$search_result= mysql_query("
            SELECT COUNT(a.IDN), a.IDN, b.location, b.age
            FROM users AS a LEFT JOIN info_search AS b 
                ON a.IDN = b.IDN  
            Where a.RoP='$s_type' AND b.Location = '$location' AND b.Age = '$age'
    ");
i=0;
while ($search=mysql_fetch_array($search_result))
{
$ar_result[] = $search; // some how I get only first row not all of them
$i++;
}

Answer 1

首先：

<?php
$location = (int) $_POST['location'];
$age = (int) $_POST['age'];
$type=$_SESSION['type'];
$and_where = array();
if( $age )
{
  $and_where [] = "b.Age = '{$age}'";
}
if( $location )
{
  $and_where [] = "b.Location = '{$location}'";
}

if( ! empty( $and_where ))
{
  $and_where = ' AND ' . implode( ' AND ', $and_where);
} else {
  $and_where = '';
}

$sql =  "SELECT COUNT(a.IDN) ".
        "FROM users AS a LEFT JOIN info_search AS b ".
        "ON a.IDN = b.IDN Where a.RoP='{$s_type}'" . $and_where;

?>

第二

$search_result= mysql_query("
            SELECT COUNT(a.IDN) as cnt, a.IDN, b.location, b.age
            FROM users AS a LEFT JOIN info_search AS b 
                ON a.IDN = b.IDN  
            Where a.RoP='$s_type' AND b.Location = '$location' AND b.Age = '$age'
    ");
i=0;
while ($search=mysql_fetch_array($search_result))
{
    $ar_result[] = $search ['cnt']; // some how I get only first row not all of them
    $i++;
}

如何发送任何操作数mysql

1 个答案: