正则表达式以限制特定字符的出现

时间:2016-02-06 06:07:16

标签: javascript angularjs regex angularjs-directive

我正在寻找常规表达式,我可以输入特殊字符出现次数的限制。

示例:我必须在整个文本中将*限制为5的最大数量,因此它应为stack***over*f**low

我在我的指令中尝试过这样:

var transformedInput = text.replace(/[^0-9][*]{6}/g, '');

但它没有用。有人可以帮帮我吗?

1 个答案:

答案 0 :(得分:0)

不确定为什么需要更换,也许您正试图阻止输入星号?无论如何,我建议你稍微扩大你的范围,并允许更多的JS来做一些繁重的工作。如果要阻止输入字符,可以在每次按键事件中检查星号的长度。

#  python code to run the hilbert curve pattern
#  from  http://www.fundza.com/algorithmic/space_filling/hilbert/basics/index.html
import sys, math

def hilbert(x0, y0, xi, xj, yi, yj, n):
    if n <= 0:
        X = x0 + (xi + yi)/2
        Y = y0 + (xj + yj)/2

        # Output the coordinates of the cv
        print '%s %s 0' % (X, Y)
    else:
        hilbert(x0,               y0,               yi/2, yj/2, xi/2, xj/2, n - 1)
        hilbert(x0 + xi/2,        y0 + xj/2,        xi/2, xj/2, yi/2, yj/2, n - 1)
        hilbert(x0 + xi/2 + yi/2, y0 + xj/2 + yj/2, xi/2, xj/2, yi/2, yj/2, n - 1)
        hilbert(x0 + xi/2 + yi,   y0 + xj/2 + yj,  -yi/2,-yj/2,-xi/2,-xj/2, n - 1)

def main():
    args = sys.stdin.readline()
    # Remain the loop until the renderer releases the helper...
    while args:
        arg = args.split()
        # Get the inputs
        pixels = float(arg[0])
        ctype = arg[1]
        reps = int(arg[2])
        width = float(arg[3])

        # Calculate the number of curve cv's
        cvs = int(math.pow(4, reps))

        # Begin the RenderMan curve statement
        print 'Basis \"b-spline\" 1 \"b-spline\" 1'
        print 'Curves \"%s\" [%s] \"nonperiodic\" \"P\" [' % (ctype, cvs)

        # Create the curve
        hilbert(0.0, 0.0, 1.0, 0.0, 0.0, 1.0, reps)

        # End the curve statement
        print '] \"constantwidth\" [%s]' % width

        # Tell the renderer we have finished
        sys.stdout.write('\377')
        sys.stdout.flush()

        # read the next set of inputs
        args = sys.stdin.readline()
if __name__ == "__main__":
    main()