Question

我正在尝试使用我的php脚本上传csv文件，但似乎只有第一行被发送到服务器。我尝试了几个解决方案，因为放q循环，但所有都没有while(! feof($handle)){ $data=fgetcsv($handle, 1000, ","); ...}，但它崩溃。

如果其他人可以帮助我。感谢。

这里是我的php脚本：

<?php
$URL = 'https://mutalyzer.nl/services/?wsdl';
?><!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>Mutalyzer SOAP client</title>
</head>
<body>
<h1>Mutalyzer SOAP client</h1>
<?php
if (isset($_GET['data']) && $_GET['data']) {
    echo $_GET['data'];
    $variant = $_GET['data'];
    echo $variant;
    //$filename = basename($_FILES['data']['name']);
    $_FILES['data']['name']=$_GET['data'];
    $filename = basename( $_FILES['data']['name']);

    $handle = fopen($filename, "r");
    $data = fgetcsv($handle, 1000, ",");

    /*while(! feof($handle)){
    $data = fgetcsv($handle, 1000, ",");
    //print_r($data);
    }*/
    //$encripData = base64_encode($variant);

    $NameChecker=$_GET['process'];
    echo '<h2>Result for '.htmlentities($variant).'</h2>';

   $options = array('features' => SOAP_SINGLE_ELEMENT_ARRAYS);

    $client = new SoapClient($URL, $options);
//while(! feof($handle)){
//$data=fgetcsv($handle, 1000, ",");
    $result = $client->submitBatchJob(array('data' => $data[0], 'process' =>$NameChecker))
                  ->submitBatchJobResult;
               //print_r(array('data' => $data, 'process' =>$NameChecker));
//}

print_r($result);
}

?>

<h2>Submit job data file to MUTALYZER</h2>

<form action="" method="GET" enctype="multipart/form-data">
<p>
Input file:
</p>
<input name="data" type="file" id="data" />
<br/>
  Process :
<input type="text" size="10" name="process" id="process" value="NameChecker"/>
<br/>
  <input type="submit" name="upload" value="Submit" />
</form>

</body>
</html>

Answer 1

尝试这样，下面的代码可以工作..

   <?php 
    // sample_file.csv file contains 35 rows.
    $row = 1; 
    $csv_array = array(); 
     if (($handle = fopen("C:\Users\develop2\Downloads\sample_file.csv", "r")) !== FALSE) {
        while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
            $csv_array[] = $data;
        }
        fclose($handle);
    }
    // here u can get the data in csv as an array with fulll rows..
    print_r($csv_array);
    ?>

Answer 2

我修改了我的源代码。我唯一的问题是服务器只获取我的数组的最后一行。我正在做一些不好的事情，但我不知道。这是我的新源代码：

<?php
$URL = 'https://mutalyzer.nl/services/?wsdl';
?><!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>Mutalyzer SOAP client</title>
</head>
<body>
<h1>Mutalyzer SOAP client</h1>
<?php
if (isset($_GET['data']) && $_GET['data']) {

    $variant = $_GET['data'];


    $_FILES['data']['name']=$_GET['data'];
    $filename = basename( $_FILES['data']['name']);
    $handle = fopen($filename, "r");
    //$data = fgetcsv($handle, 1000, ",");


    $NameChecker=$_GET['process'];
    echo '<h2>Result for '.htmlentities($variant).'</h2>';

   $options = array('features' => SOAP_SINGLE_ELEMENT_ARRAYS);

    $client = new SoapClient($URL, $options);
$data=array();
while(! feof($handle)){
    $data = fgetcsv($handle, 1000);

    $result = $client->submitBatchJob(array('data' => $data[0], 'process' =>$NameChecker))
                  ->submitBatchJobResult;
               print_r(array('data' => $data, 'process' =>$NameChecker));
            }  
print_r($result); 
}

?>

<h2>Submit job data file to MUTALYZER</h2>

<form action="" method="GET" enctype="multipart/form-data">
<p>
Input file:
</p>
<input name="data" type="file" id="data" />
<br/>
  Process :
<input type="text" size="10" name="process" id="process" value="NameChecker"/>
<br/>
  <input type="submit" name="upload" value="Submit" />
</form>

</body>
</html>

PHP将csv文件上传到服务器阵列

2 个答案: