Question

我想形成数组，如下所示。我如何在foreach中形成以下内容：

    SELECT [rank] FROM table 
      ORDER BY
       CASE  
          WHEN [rank] LIKE 'CHA%' THEN 1
          WHEN [rank] LIKE 'MAS%' THEN 2
          WHEN [rank] LIKE 'DIA%' THEN 3
          WHEN [rank] LIKE 'PLA%' THEN 4
          WHEN [rank] LIKE 'GOL%' THEN 5
          WHEN [rank] LIKE 'SIL%' THEN 6
          WHEN [rank] LIKE 'BRO%' THEN 7
          WHEN [rank] LIKE 'Unranked' THEN 8
          WHEN [rank] LIKE 'No Data' THEN 9
          ELSE 10
       END;

我的代码：

{
  "status": "SUCCESS",
  "totalRecords": 3,
  "errorMessage": "",
  "organizations": [
    {
      "organizationId": 1
    },
    {
      "organizationId": 2
    }
  ]
}

上面的代码，我想改变这样的事情：

$orgArray =  array();
foreach($organizationInterface as $organization){
    $orgArray[] = array(
        'organizationId' => $organization->getId()
    );
}

Answer 1

根据我的理解，你想要这样的东西：

    foreach($organizationInterface as $organization){
        $orgArr['organizationId'][] = $organization->getId();
    }

您不能在单个数组键上拥有多个值，这就是您想要在那里执行的操作。

Answer 2

$jsonString = '{
    "status": "SUCCESS",
    "totalRecords": 3,
    "errorMessage": "",
    "organizations": [
       {
         "organizationId": 1
       },
       {
         "organizationId": 2
       }
     ]
}';

$jsonObj = json_decode($jsonString);
echo 'Status: ' . $jsonObj->status;
foreach($jsonObj->organizations as $org) { 
   echo 'Organization ID: ' . $org->organizationId;
}

在PHP中阵列形成

2 个答案: