我试图用运算符替换包含值的字符串:like" 2456:72"到" 2456.72"从mysql获取数据的地方,我尝试使用str_replace
这很糟糕。 $row_loop3["Tot_minutes"]
是我应该替换字符的行,请找到我的代码:
$mysqli = new mysqli("172.16.10.102", "******", "RND@ISO-3306", "eTrans");
if (!$mysqli->multi_query("call sp_get_Android_Online_minutes_Chart ('2015-01-01','2016-01-30')")) {
$response["success"] = 0;
}
do {
if ($res_loop3 = $mysqli->store_result()) {
$response_loop3["minutes"] = array();
$find = ":";
$re = ".";
while ($row_loop3 = $res_loop3->fetch_assoc()) {
$j = 5;
$value_loop3 = array();
$value_loop3["File_Day"] = $row_loop3["edit_date"];
$value_loop3["File_Minutes"] = $row_loop3["FileDay"];
$val["Tot1_Minutes"] = $row_loop3["Tot_minutes"];
$value_loop3["Total_Minutes"] = str_replace($val, $find, $re); //value which I should replace : with .
array_push($response_loop3["minutes"], $value_loop3);
$response_loop3["success"] = 1;
}
echo $merger = json_encode(array_merge($response, $response_loop2, $response_loop3));
$res->free();
}
} while ($mysqli->more_results() && $mysqli->next_result());
请帮助我,提前谢谢
答案 0 :(得分:1)
您不是在制作变量,而是在制作关联数组。 改变这个
$val["Tot1_Minutes"] = $row_loop3["Tot_minutes"];
到
$val= $row_loop3["Tot_minutes"];
并且还将str函数命令为
$val = $row_loop3["Tot_minutes"];
$value_loop3["Total_Minutes"]=str_replace($find,$re,$val);
答案 1 :(得分:1)
str_replace
应该以这种方式使用:
str_replace( mixed $search , mixed $replace , mixed $subject [, int &$count ] )
函数的参数是search,replace和subject,所以对于你的情况应该是:str_replace($find,$re,$val)