PHP替换从mysql获取的字符串中的字符

时间:2016-02-03 07:46:38

标签: php mysql

我试图用运算符替换包含值的字符串:like" 2456:72"到" 2456.72"从mysql获取数据的地方,我尝试使用str_replace这很糟糕。 $row_loop3["Tot_minutes"]是我应该替换字符的行,请找到我的代码:

$mysqli = new mysqli("172.16.10.102", "******", "RND@ISO-3306", "eTrans");
if (!$mysqli->multi_query("call sp_get_Android_Online_minutes_Chart ('2015-01-01','2016-01-30')")) {
    $response["success"] = 0;
}
do {
    if ($res_loop3 = $mysqli->store_result()) {
        $response_loop3["minutes"] = array();
        $find                      = ":";
        $re                        = ".";

        while ($row_loop3 = $res_loop3->fetch_assoc()) {
            $j                            = 5;
            $value_loop3                  = array();
            $value_loop3["File_Day"]      = $row_loop3["edit_date"];
            $value_loop3["File_Minutes"]  = $row_loop3["FileDay"];
            $val["Tot1_Minutes"]          = $row_loop3["Tot_minutes"];
            $value_loop3["Total_Minutes"] = str_replace($val, $find, $re); //value which I should replace : with .
            array_push($response_loop3["minutes"], $value_loop3);
            $response_loop3["success"] = 1;
        }

        echo $merger = json_encode(array_merge($response, $response_loop2, $response_loop3));

        $res->free();
    }
} while ($mysqli->more_results() && $mysqli->next_result());

请帮助我,提前谢谢

2 个答案:

答案 0 :(得分:1)

您不是在制作变量,而是在制作关联数组。 改变这个

 $val["Tot1_Minutes"] = $row_loop3["Tot_minutes"];

 $val= $row_loop3["Tot_minutes"];

并且还将str函数命令为

$val = $row_loop3["Tot_minutes"];
$value_loop3["Total_Minutes"]=str_replace($find,$re,$val);

答案 1 :(得分:1)

str_replace应该以这种方式使用:

str_replace( mixed $search , mixed $replace , mixed $subject [, int &$count ] )

函数的参数是search,replace和subject,所以对于你的情况应该是:str_replace($find,$re,$val)