AngularJS $过滤器在控制器中具有相同属性的条件或条件

时间:2016-02-02 13:58:34

标签: angularjs angularjs-filter

控制器:

var myApp = angular.module('myApp', []);

myApp.controller('myCtrl', ['$scope', '$filter', function($scope, $filter){

    $scope.tickets = [
                      {title : 'ticket1', assignee : {id:'pratap', name: 'PRATAP'}},
                      {title : 'ticket2', assignee : null},
                      {title : 'ticket3', assignee : {id:'ak', name: 'AK'}}
                      ];    

    $scope.defaultOption = 1;
    $scope.options = [
                      {id:1, name : 'MY TICKETS'},
                      {id:2, name : 'OTHERS TICKET'}
                      ];

    $scope.filteredTicket = [];

    $scope.filterData = function(criteria) {
        if (criteria == 1) {
            $scope.filteredTicket = $filter('filter')($scope.tickets, {assignee: {id:'pratap'}});
        } else {
            $scope.filteredTicket = $filter('filter')($scope.tickets, {assignee: null, assignee: {id:'ak'}});
            console.log($scope.filteredTicket);
        }


    };

    $scope.filterData($scope.defaultOption);

}]);

HTML:

<div ng-controller="myCtrl">
<div>Current User: pratap</div>
<div>
    FILTER: <select ng-model="defaultOption" ng-change="filterData(defaultOption)" ng-options="option.id as option.name for option in options"></select>
</div>
    <div>
        <h1>Tickets</h1>
        <ul>
            <li ng-repeat="ticket in filteredTicket">{{ticket.title}}</li>
        </ul>
    </div>  
</div>  

我想知道是否可以在$ filter中使用相同的对象属性来形成或条件,如下所示

$scope.filteredTicket = $filter('filter')($scope.tickets, {assignee: null, assignee: {id:'ak'}});

这样我就得到了两个拥有受让人的对象:null和受让人:&#39; ak&#39;。如果我选择OTHERS TICKETS,我需要取消ticket2和ticket3,但截至目前我只得到ticket3。

有人可以帮忙吗?

Created-Plunker-Here

3 个答案:

答案 0 :(得分:10)

您可以在过滤器的表达式中添加一个函数:

$scope.filteredTicket = $filter('filter')($scope.tickets, function(value){
        return value.assignee === null || value.assignee.id === 'ak';
});

Plunkr

答案 1 :(得分:1)

只需使用Array.prototype.filter方法手动过滤,然后您就可以获得更大的灵活性:

$scope.filterData = function(criteria) {
  if (criteria == 1) {
    $scope.filteredTicket = $scope.tickets.filter(function(ticket) {
      return ticket.assignee === null || ticket.assignee.id == 'pratap';
    });
  } 
  else {
    $scope.filteredTicket = $scope.tickets.filter(function(ticket) {
      return ticket.assignee === null || ticket.assignee.id == 'ak';
    });
    console.log($scope.filteredTicket);
  }
};

演示: https://plnkr.co/edit/MyYfkKzYdJmdAeFHYEvw?p=preview

答案 2 :(得分:0)

签出

var rateSelected = $filter('filter')($scope.GradeList, function (obj) {
                        if(obj.GradeId == $scope.contractor_emp.save_modal_data.GradeId)
                        return obj;
                });