[：bash脚本中的参数错误太多了

Question

编辑：正如@Biffen的建议，将${SCRIPTS[*]} =~ ${ARG}置于双括号中就可以了。

E.G。 if [[ ${SCRIPTS[*]} =~ ${ARG} ]]; then

我正在尝试将进程名称作为数组，并检查给定的文件名是否存在于该数组中。

当我尝试运行脚本时，它会在if [ ${SCRIPTS[*]} =~ ${ARG} ]; then行引发错误。我不知道为什么我会收到这个错误。

#!/usr/bin/env bash

SCRIPTS=(`ps x | grep python | grep -v ".pyc" | grep -v grep | awk  '{print $NF}'`)
ARGS="$@"

kill_funct () {
    if [ !-z "$1" ]; then
        # kill -9 "$1"
        echo "$1 is killed."
    fi
}

killall_funct () {
    for SCRIPT in SCRIPTS
        do
            # kill -9 ${SCRIPT}
            echo "${SCRIPT} is killed."
        done
}

for ARG in ${ARGS}
do
    if [ -z ${ARG} ]; then
        echo "No file name or key given as parameter."
        echo "For help please use -h key."
    elif [ ${ARG} = "-h" ]; then
        echo "USAGE:"
        echo "   -h          : Displays this help"
        echo "   \"file name\" : Kills the process of the given file names"
        echo "                 You can give more than one file name as argument"
        echo "                 E.G. bash oldur.sh \"file1 name\" \"file2 name\" ..."
        echo "   All         : This parameter kills all python processes found with 'ps' command"
    elif [ ${ARG} = "All" ]; then
        killall_funct
    else
        echo ${SCRIPTS}
        if [ ${SCRIPTS[*]} =~ ${ARG} ]; then
            kill_funct ${ARG}
        else
            echo "${ARG} not present as a process."
        fi
    fi
done