我正在使用org.apache.commons.fileupload
上传。
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
GWT.log("is multipart? " + Boolean.toString(isMultipart), null);
ServletFileUpload upload = new ServletFileUpload();
try{
FileItemIterator iter = upload.getItemIterator(request);
while (iter.hasNext()) {
FileItemStream item = iter.next();
String name = item.getFieldName();
InputStream stream = item.openStream() ;
/**
* Save th uploaded file
*/
}
}
catch(Exception e){
e.printStackTrace();
}
}
如何保存上传的文件?
答案 0 :(得分:2)
这看起来像服务器端代码,(除了GWT-RPC servlet之外)根本不特定于GWT。那个GWT.log()
是不必要的 - 用常规的日志记录调用替换它,并像往常一样在非GWT代码中处理上传,因为它就是这样。
Here is a helpful example of using apache's fileupload to get you started
答案 1 :(得分:2)
我认为这可以帮到你。
if (!item.isFormField()) {
String fieldName = item.getFieldName();
String fileName = item.getName();
String contentType = item.getContentType();
boolean isInMemory = item.isInMemory();
long sizeInBytes = item.getSize();
File saveTo = new File("/file_uploads/" + fileName);
try {
item.write(saveTo);
...
}
catch (Exception e){
...
}
请注意,上传的文件可能已由org.apache.commons.fileupload自动保存
您可以使用
设置要保存在磁盘上或加载到内存中的文件的大小阈值// Create a factory for disk-based file items
DiskFileItemFactory factory = new DiskFileItemFactory();
// Set factory constraints
factory.setSizeThreshold(yourMaxMemorySize);
factory.setRepository(yourTempDirectory);
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
// Set overall request size constraint
upload.setSizeMax(yourMaxRequestSize);
// Parse the request
List /* FileItem */ items = upload.parseRequest(request);
您需要了解的有关org.apache.commons.fileupload的所有内容均在此处:Using FileUpload