python:检查任意数量的嵌套列表,如果为空则结束

时间:2016-01-28 19:50:56

标签: python

所以基本上我试图创建一个函数来检查列表,该列表可能包含或不包含许多嵌套的列表层,以查看它们是否都是空的。

所以

empty([])将返回true,因此empty([['']])也会empty([[[]]])

我已经尝试了

def empty(seq):
     try:
         return all(map(empty, seq))
     except TypeError:
         return False

但在运行时遇到RuntimeError: maximum recursion depth exceeded错误。

有问题的案例字符串是这样的:["[u'3D Blu-ray Disc\\u2122 Player (BD-D7500)']"]我不知道为什么会导致这个问题

["[u'3D Blu-ray Disc\\u2122 Player (BD-D7500)']"]
maximum recursion depth exceeded in cmp
Traceback (most recent call last):
  File "./dashboard.py", line 583, in download
    return get_rows_from_db(str(job.id), job.url,taskid, options,trial)
  File "./dashboard.py", line 123, in get_rows_from_db
    print "B " + empty(col)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "./dashboard.py", line 52, in empty
    for item in seq)
  File "./dashboard.py", line 52, in <genexpr>
    for item in seq)
  File "/usr/lib/python2.7/abc.py", line 132, in __instancecheck__
    if subclass is not None and subclass in cls._abc_cache:
  File "/usr/lib/python2.7/_weakrefset.py", line 73, in __contains__
    return wr in self.data
RuntimeError: maximum recursion depth exceeded in cmp

3 个答案:

答案 0 :(得分:1)

def empty(L_or_I):
    if not L_or_I:
       return True
    if isinstance(L_or_I,(list,tuple)):
       return all(empty(x) for x in L_or_I)
    return False

我想......也许

答案 1 :(得分:1)

如果0的列表是&#34;空&#34;,Joran答案肯定是正确的。

如果您只想检查可迭代,我建议:

import collections
def empty(e):
    if not isinstance(e, collections.Iterable):
        return False
    if not e:
        return True
    return all(empty(x) for x in e)

答案 2 :(得分:1)

此功能可满足您提供的每个测试用例。

import collections


def empty(seq):
    if isinstance(seq, basestring):
        return seq == ''
    return all(empty(item)
               if isinstance(item, collections.Sequence)
               else False
               for item in seq)

assert empty([])
assert empty([['']])
assert empty([[[]]])
assert not empty([[[], 1]])
assert empty(u'')
assert not empty(u'1')
assert not empty(["[[u'3D Blu-ray Disc\\u2122 Player (BD-D7500)']"])