Question

我写了一个应该打印json调用响应的php代码。但我得到NULL输出。我已经检查过我的json调用从restclient工作正常。

这是我的代码

<?php

    $username = "user";
    $password = "password";

    $postData = array(
            'username' => $username,
            'password' => $password,
            'msisdn' => "111111111"
            );

    $ch = curl_init('http://ip:<port>/xxx/yyy/zzz');

    curl_setopt_array($ch, array(
    CURLOPT_POST => TRUE,
    CURLOPT_RETURNTRANSFER => TRUE,
    CURLOPT_HTTPHEADER => array(
        'Content-Type: application/json'
    ),
    CURLOPT_POSTFIELDS => json_encode($postData)
    ));

    // Send the request
    $response = curl_exec($ch);

    // Check for errors
    if($response === FALSE){
    die(curl_error($ch));
    }

    // Decode the response
    $responseData = json_decode($response, TRUE);

    // Print the date from the response
    echo $responseData['published'];

    var_dump($responseData);

    ?>

提前致谢。

Answer 1

尝试：

$responseData = json_decode($response, true);
if (json_last_error() !== JSON_ERROR_NONE) {
    throw new \RuntimeException('Invalid JSON.');
}

Answer 2

好吧所以我已经解决了我的问题并重新编写了代码。我实际上没有在json字段中提供正确形式的用户名和密码，这实在是一个愚蠢的错误。我在这里提供更新的代码 `

$data = array("user" => "$username", "pass" => "$password", "msisdn" => "$msisdn");
$data_string = json_encode($data);

$ch = curl_init('http://ip:port/call_center/account/general');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5);

//execute post
$result = curl_exec($ch);

//close connection
curl_close($ch);

echo $result;


?>`

谢谢大家。

如何从php调用json

2 个答案: