Question

我有一个字符串，让我们说： "The student John with the number 1 is smart."

我想提取此字符串的可变部分：学生的姓名及其编号。

"The student John with the number 1 is smart."
"The student Alan with the number 2 is smart."

我应该如何创建正则表达式？我知道\\d提取数字，但我怎样才能提取字符串？

but for the "**H2k Gaming** (1st to **5** Kills)"

其中变量字符串是“H2k Gaming”，变量号是5
```
String sentence = "H2k Gaming (1st to 5 Kills)";
String pattern = "[\\w ]+ \$1st to (\\d+) Kills\$";
```

打印：

Name: Gaming
Number: 5

Answer 1

String sentence = "The student John with the number 1 is smart.";
String pattern = "The student (\\w+) with the number (\\d+) is smart.";

Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(sentence);

if(m.find()) {
    System.out.println("Name: " + m.group(1));
    System.out.println("Number: " + m.group(2));
}

See it in action

Answer 2

如果字符串始终具有相同的格式，您可以简单地按" "拆分并访问正确的索引：

String[] tokens = text.split(" ");
String name = tokens[2];
int number = Integer.parseInt(tokens[6]);

Answer 3

只要形式不变，就得到空白。

^The student (.*) with the number (.*) is smart\.$

使用java模式和匹配器从字符串中提取变量字符串和数字

3 个答案: