我们在配置单元中尝试了以下查询。但得到错误。请帮我解决这个问题。
select count(1) as OpenItems from issues i , issue_statuses s
where s.id = i.status_id
and s.name NOT IN ('Closed','Passed','Rejected','On
Hold','Baselined','Completed')
and i.project_id IN
(select id from projects3 from
CASE WHEN ${projectname} = 'All' then id in
(select p.id from members m, projects3 p ,users_1 u
where m.project_id = p.id and u.id = m.user_id and u.status = '1'
and u.id IN
(select u1.id from users_1 u1, Supervisor_hierarchy s1 where u1.mail = s1.email and s1.name = ${Superisorname})
group by p.id)
WHEN (${projectname} <>'All' and ${SubProject projectname} ='All') then id
IN (select id from (select id from project_closure where parent_id in (select id from projects where name = ${projectname}) group by id)a)
WHEN (${SubProject projectname}<>'All' and ${projectname}<> 'All') then id
IN (select id from(select id from project_closure where id in (select id from projects where name = ${SubProject projectname}) group by id)a)
END
order by id)
错误:6:5不支持的SubQuery Expression'id':SubQuery表达式引用Parent和SubQuery表达式,并且不是有效的连接条件。
答案 0 :(得分:0)
我知道现在已经很晚了,但却面对任何遇到此问题的人。
当我们遇到以下一个或多个Hive子查询限制时,就会出现此问题。
在这种情况下,对父查询的引用用于Group By子句,该子句属于第4个限制。
Hive子查询限制
Source: https://cwiki.apache.org/confluence/display/Hive/LanguageManual+SubQueries