我有两个名为Screen
和Window_mgr
的课程。
Screen
允许Window_mgr
通过友元函数声明修改其私有/受保护成员。
结果Window_mgr
在代码的最后定义了一个名为Window_mgr::clear
的非成员函数,它应该使用它。
不幸的是,我得到了一些我无法解释的荒谬错误。
我错过了什么?
#pragma once
#ifndef SCREEN_H
#define SCREEN_H
#include <string>
#include <vector>
class Window_mgr {
public:
// location ID for each screen on the window
using ScreenIndex = std::vector<Screen>::size_type;
// reset the Screen at the given position to all blanks
void clear(ScreenIndex);
private:
std::vector<Screen> screens{ Screen(24, 80, ' ') };
};
class Screen {
public:
// Friends
friend void Window_mgr::clear(ScreenIndex);
//friend class Window_mgr;
// Fields
// typedef => creates an alias
// typedef std::string::size_type pos;
// alternative way to declare a type member using a type alias
using pos = std::string::size_type;
// Constructors
Screen() = default; // needed because Screen has another constructor
// cursor initialized to 0 by its in-class initializer
Screen(pos ht, pos wd, char c) : height(ht), width(wd), contents(ht * wd, c) {} // get the character at the cursor
Screen &display(std::ostream &os) // function is in the class body => implicitly inline
{
do_display(os);
return *this;
}
const Screen &display(std::ostream &os) const // function is in the class body => implicitly inline
{
do_display(os);
return *this;
}
// Methods
char get() const { return contents[cursor]; } // implicitly inline
inline char get(pos ht, pos wd) const; // explicitly inline
Screen &move(pos r, pos c); // can be made inline later
Screen &set(char);
Screen &set(pos, pos, char);
private:
// Fields
mutable size_t access_ctr;
pos cursor = 0;
pos height = 0, width = 0;
std::string contents;
// Methods
void do_display(std::ostream &os) const { os << contents; }
};
inline Screen &Screen::set(char c)
{
contents[cursor] = c; // set the new value at the current cursor location
return *this; // return this object as an lvalue
}
inline Screen &Screen::set(pos r, pos col, char ch)
{
contents[r*width + col] = ch; // set specified location to given value
return *this; // return this object as an lvalue
}
// we can specify inline on the definition
inline Screen &Screen::move(pos r, pos c) {
pos row = r * width; // compute the row location
cursor = row + c; // move cursor to the column within that row
return *this; // return this object as an lvalue
}
char Screen::get(pos r, pos c) const // declared as inline in the class
{
pos row = r * width; // compute row location
return contents[row + c]; // return character at the given column
}
void Window_mgr::clear(ScreenIndex i)
{
// s is a reference to the Screen we want to clear
Screen &s = screens[i];
// reset the contents of that Screen to all blanks
s.contents = string(s.height * s.width, ' ');
}
#endif
答案 0 :(得分:5)
您无法在Screen
类中声明Window_mgr
个对象的向量,因为编译器在此代码中不知道Screen
。如果要声明指针向量,可以通过向前声明Screen
来修复它,但对于实际对象的向量,必须有完整定义。
您需要切换Window_mgr
和Screen
的顺序,并将友谊声明为Window_mgr
类:
class Screen {
public:
friend class Window_mgr;
...
};
class Window_mgr {
public:
// location ID for each screen on the window
using ScreenIndex = std::vector<Screen>::size_type;
// reset the Screen at the given position to all blanks
void clear(ScreenIndex);
private:
std::vector<Screen> screens{ Screen(24, 80, ' ') };
};
为什么编译器知道
Window_mgr
但不知道Window_mgr::ScreenIndex
C ++对友谊声明中使用的类名有一个特殊规则:
如果尚未声明朋友声明中使用的类的名称,则会在现场向前声明。
这就是编译器&#34;知道&#34; Window_mgr
的{{1}}(即它没有;它接受你的话)。成员函数或成员类型中没有这样的规则&#34; befriended&#34;类。这就是编译器不知道Window_mgr::ScreenIndex
。
答案 1 :(得分:0)
我建议不要使用&#34;朋友&#34;为此..只需将一个clear()公共成员函数添加到类Screen,并从窗口管理器中调用它
// declaration
Screen &clear();
// definition
inline Screen &Screen::clear() {
contents.resize(height * width, ' ');
return *this; // return this object as an lvalue
}
// use
void Window_mgr::clear(ScreenIndex i)
{
// s is a reference to the Screen we want to clear
Screen &s = screens[i];
// reset the contents of that Screen to all blanks
s.clear();
}
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