Question

我试图从VB.Net中的Alfresco WSDL读取SOAP地址。

XML看起来像这样：

<?xml version="1.0" encoding="utf-8"?>
<definitions xmlns:cmis="http://docs.oasis-open.org/ns/cmis core/200908/" xmlns:cmism="http://docs.oasis-open.org/ns/cmis/messaging/200908/" xmlns:cmisw="http://docs.oasis-open.org/ns/cmis/ws/200908/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:ns="http://schemas.xmlsoap.org/soap/encoding/" targetNamespace="http://docs.oasis-open.org/ns/cmis/ws/200908/" xmlns:jaxws="http://java.sun.com/xml/ns/jaxws" name="CMISWebServices">
   ...
   <message name="cmisException">
       <part name="fault" element="cmism:cmisFault" />
   </message>
   ...
   <service name="ACLService">
       <port name="ACLServicePort" binding="cmisw:ACLServicePortBinding">
           <soap:address location="https://myserver:8443/alfresco/cmisws/ACLService" />
       </port>
   </service>
   ...

这是我的VB.Net代码。我试图将XmlDocument.SelectNodes()与XPath查询一起使用......而且我没有快乐。

    Dim xmlReader As System.Xml.XmlTextReader = New XmlTextReader(urlWsdl)
    Dim xmlWsdl As System.Xml.XmlDocument = New XmlDocument
    xmlWsdl.Load(xmlReader)
    ...
    Dim xPath As String = "/definitions/service[@name='" & sService & "']"
    Dim serviceNodes As XmlNodeList
    While True
        Try
            serviceNodes = xmlWsdl.SelectNodes(xPath)
            PrintMsg("Count=" & serviceNodes.Count)
        Catch ex As Exception
            Logger.LogMsg("ERROR: " & ex.Message)
        End Try
    End While
    ...

我需要从WSDL获取几个不同服务的地址位置：＆＃34; ACLService＆＃34;，＆＃34; DiscoveryService＆＃34;，＆＃34; MultiFilingService＆＃34;，＆＃34; NavigationService＆＃34;等等。

我尝试了很多不同的XPath表达式，但我总是得到＆＃34; serviceNodes.Count＆＃34; ＆＃34; 0＆＃34;：

Dim serviceNodes As XmlNodeList = xmlWsdl.SelectNodes(xPath):

XPath:                                    Count:   ServicesNodes(0).OuterXml:
-----                                     -----    -------------------------
//service[@name='ACLService']             0
//service[@name=ACLService]               0
//service                                 0
*                                         1        OuterXml: "<definitions ...>...  // Entire XML document
/definitions//service[@name=ACLService]   0
/definitions/service[@name='ACLService']  0
/definitions/service                      0

问：我做错了什么？

问：我能做些什么来解决它？

=============================================== ====

非常感谢har07，他正确地指出我需要使用XmlNamespaceManager。

以下是更新后的代码：

Dim nsManager As New XmlNamespaceManager(New NameTable())
nsManager.AddNamespace("afws", xmlWsdl.DocumentElement.NamespaceURI)
Dim xPath As String = "/afws:definitions/afws:service[@name='" & sService & "']"
Dim serviceNodes As XmlNodeList = xmlWsdl.SelectNodes(xPath, nsManager) ' Now works perfectly!

Answer 1

＆＃34;我做错了什么？＆＃34;

您的XPath没有考虑默认命名空间，在此处声明没有前缀的那个：xmlns="http://schemas.xmlsoap.org/wsdl/"。（有关详细信息，请参阅this MSDN article中的 默认命名空间 部分）。

＆＃34;我该怎么做才能修复它？＆＃34;

使用XmlNamespaceManager注册前缀到默认命名空间URI的映射，然后在XPath中正确使用已注册的前缀，例如：

....
Dim nsManager As New XmlNamespaceManager(New NameTable())
nsManager.AddNamespace("d", xmlWsdl.DocumentElement.NamespaceURI)
Dim xPath As String = "/d:definitions/d:service[@name='" & sService & "']"
....
serviceNodes = xmlWsdl.SelectNodes(xPath, nsManager)

VB.Net XmlDocument.SelectNodes（xPath）：无法查询WSDL

1 个答案: