我有一个这样的对象:
var objectName = { "290" : "Cat1", "293" : "Cat2", "295" : "Cat1" }
如何对具有相同值的元素的输出进行排序?
我需要这样的东西:
var sortByCat = 'Cat1: 290, 295; Cat2: 293';
Javascript或jQuery可以正常工作。
答案 0 :(得分:1)
这个问题有点不正统,但不确定为什么会被投票。无论如何,你可以这样做:
https://jsfiddle.net/wfyndq7x/
var obj = { '290': 'Cat1', '293': 'Cat2', '295': 'Cat1' };
var sortByCat = {}
for (var num in obj) {
if (obj.hasOwnProperty(num)) {
if (sortByCat[obj[num]] == null)
sortByCat[obj[num]] = num;
else
sortByCat[obj[num]] += ', ' + num;
}
}
var catString = ''
for (var catData in sortByCat) {
if (sortByCat.hasOwnProperty(catData)) {
catString += catData + ': ' + sortByCat[catData] + '; ';
}
}
基本上将其转换为哈希,将密钥作为cat,并将数字附加为值。然后转换为字符串,以便打印它。
答案 1 :(得分:1)
类似的东西:
var map = {};
var obj = { "290" : "Cat1", "293" : "Cat2", "295" : "Cat1" };
for (var i in obj)
{
var val = obj[i];
if (!map[val]) map[val] = [];
map[val].push(i);
}
console.log(map);
答案 2 :(得分:1)
这应该这样做:
var obj = {
"290": "Cat1",
"293": "Cat2",
"295": "Cat1",
"291": "Cat1",
"292": "Cat2",
"297": "Cat3"
}
var res = JSON.stringify(Object.keys(obj).reduce(function(res, key) {
if (res[obj[key]]) res[obj[key]].push(key)
else res[obj[key]] = [key];
return res;
}, {})).replace(/([,:])/g, "$1 ").replace(/],/g, "]; ").replace(/[{}\[\]"]/g, "");
document.body.innerHTML = res;
答案 3 :(得分:1)
这是一个将分组数据返回到另一个对象的函数。
中查看var objectName = { "290": "Cat1", "293": "Cat2", "295": "Cat1" };
function groupByValue(_objectName) {
var sorted = {};
for (var obj in _objectName) {
sorted[_objectName[obj]] = sorted[_objectName[obj]] || [];
sorted[_objectName[obj]].push(obj);
}
return sorted;
}
//{"Cat1":["290","295"],"Cat2":["293"]}
答案 4 :(得分:1)
var objectName = { "290" : "Cat1", "293" : "Cat2", "295" : "Cat1" };
// build a map where key is category name and value are its associated numbers
var categories = {};
for (var num in objectName) {
var name = objectName[num];
if (!categories.hasOwnProperty(name)) {
categories[name] = [];
}
categories[name].push(num);
}
// create formatted string
var sortByCat = '';
for (var name in categories) {
sortByCat += name + ': ' + categories[name].join(', ') + '; ';
}
console.log(sortByCat);