Question

我想在点击提交按钮后使用jQuery（发布请求时调用ajax）和Java将我的json数据对象保存到Postgresql中，请帮我这样做？提前谢谢。

html：

(function() {
  var testValue;
  testValue = {};
  $('input[id=buttonId]').click(function() {
    var name;
    name = $(this).attr('name');
    testValue[name] = $(this).val();
  });
  $('#submit').click(function() {
    $('input[id=fileId]').each(function($i) {
      var name;
      name = $(this).attr('name');
      testValue[name] = $(this).val();
    });
    console.log(JSON.stringify(testValue));//it gives the json data object, after clicking on Submit button`[ex: {"firstButton":"button1","secondButton":"button2","file":"test.txt"} ]`
  });
})();

Postgresql表：create table savedata(id integer primary key, content json);

凭证：

db.default.driver=org.postgresql.Driver
db.default.url="jdbc:postgresql://localhost:5432/dbname"
db.default.user=test
db.default.password=test

HTML：

<input type='button' value='button1' class='button' id="buttonId" name='firstButton'/>
<input type='button' value='button2' class='button' id="buttonId" name='secondButton'/>
<input type='file' name='file' id="fileId" value='file upload'/>
<input type='submit' value='submit' id='submit'>

Answer 1

我首先在java中编写HTTP server，然后接受来自javascript的POST请求。您也很聪明地在其中添加某种形式的authentication，因此不是每个人都可以添加记录。您还可以使用我将使用的framwork。

只要POST请求带有JSON数据和所需的授权，您就可以让Java将JSON解析为数据库的Insert语句。

现在是Javascript部分：您最好使用jQuery使用ajax发送JSON编码数据。使用POST请求。

在这种情况下，它看起来像使用：

http://www.tutorialspoint.com/postgresql/postgresql_java.htm
How to parse a JSON and turn its values into an Array?

http://restx.io/docs/ref-core.html

mode_211
enable_trace
establish_context
enable_trace
card_connect
open_sc -security 1 -keyind 0 -keyver 0 -mac_key 404142434445464748494a4b4c4d4e4f -enc_key 404142434445464748494a4b4c4d4e4f // Open secure channel
Command --> 80CA006600
Wrapped command --> 80CA006600
Response <-- 664C734A06072A864886FC6B01600C060A2A864886FC6B02020101630906072A864886FC6B03640B06092A864886FC6B040215650B06092B8510864864020103660C060A2B060104012A026E01029000
Command --> 80500000089AA60E4925924D6900
Wrapped command --> 80500000089AA60E4925924D6900
Response <-- 000011370001AB741C0BFF02047E4413D6E4873750AB69F325A1E4FF9000
Command --> 848201001056D480DA94FF6A33778F6D68A7497C8C
Wrapped command --> 848201001056D480DA94FF6A33778F6D68A7497C8C
Response <-- 9000
put_sc_key -keyver 1 -newkeyver 1 -mac_key 404142434445464748494a4b4c4d4e4e -enc_key 404142434445464748494a4b4c4d4e4e -kek_key 404142434445464748494a4b4c4d4e4e -cur_kek 404142434445464748494a4b4c4d4e4f
Error: unknown option -cur_kek

的jQuery

// Create a method that handles a POST request. In this case to "/message"
@POST("/message/}")
public Message insertInDb(Message msg // body param
                        ) {
    // Decode the JSON to an array object so you can loop it for insert statement(s)           
   JSONArray json = new JSONArray(msg);
    /////////////////////////////////////////////////////////////////////
  // Create the postgre connection
  Connection c = null;
  Statement stmt = null;
  try {
     Class.forName("org.postgresql.Driver");
     c = DriverManager
        .getConnection("jdbc:postgresql://localhost:5432/testdb",
        "manisha", "123");
     c.setAutoCommit(false);
     System.out.println("Opened database successfully");

     stmt = c.createStatement();

     // Use the JSON data instead below for the INSERT statement:
     String sql = "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) "
           + "VALUES (1, 'Paul', 32, 'California', 20000.00 );";
     stmt.executeUpdate(sql);


     stmt.close();
     c.commit();
     c.close();
  } catch (Exception e) {
   return  e.getClass().getName()+": "+ e.getMessage();

  }
    return "success";
}

如何使用jQuery Post和Java在PostgreSQL中保存json数据？

1 个答案: