如何在javascript变量中存储上述图像标记的图像src?
<img class="preview" alt="Styling with a Bandana" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg" onmouseover="upDate(this)" onmouseout="unDo()">
我需要网址,所以我可以在这里输入
document.getElementById("image").style.backgroundImage = "url(' + imgsrc + ')";
并获取背景图片
答案 0 :(得分:0)
jQuery = .attr('src');
js = .getAttribute('src');
答案 1 :(得分:0)
var imgsrc = document.getElementsByClassName("preview");
document.body.style.backgroundImage = "url('"+ imgsrc +"')";